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3 years ago

What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases?

Physics

1 answer:

Contact [7]3 years ago

6 0

Answer:

It remains the same

Explanation:

Atomic number is the number of protons in a nucleus so no effect due to change of neutrons.

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What is the pressure in a gas container that is connected to an open-end U-tube manometer if thepressure of the atmosphere is 75

VARVARA [1.3K]

Answer:

The pressure in a gas container is 839.44mmHg

Explanation:

Density of Mercury = 13.56g/cm³ = 13556kg/m³

$P_{A} = P_{0} +$ hρg/ P₀

where, g= acceleration due to gravity, 10m/s²

h= height= 8.6cm = 0.086m

$P_{A}$ = hρg/ P₀

= 0.086 × 13556 × 10

= 11658.16 kgm/ m²s²

= 11658.16 N/m² = 11658.16pa

= 87.4434mmHg

where 1 torr = 1mmHg

$P_{0}$ = 752torr = 752mmHg

$P_{A$ = 752 + 87.4434

= 839.44mmHg

4 0

3 years ago

A pan hangs from a 50 cm spring. When a 10 kg mass is placed in the pan, it stretches the spring 6 cm. What is a function rule l

MrRissso [65]

Answer:

Explanation:

A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

$F = -kx$

F is the force applied and x is the elongation of the spring

k is the spring constant.

negative sign indicates the change in direction from equilibrium position.

In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

$F=mg$

Inserting this into Hooke's Law

$mg=-kx$

computing it for x,

$-x=mg/k$

This is the model which will tell the length of the spring against change in the mass located in the pan.

3 0

3 years ago

A child uses her hand to measure the width of a table too. Her hand has a width of 6.9 cm at its widest points, and she finds th

daser333 [38]

20/45/1 step by step explanation

4 0

3 years ago

Please answer formula is in text

Travka [436]

E=mc^2 n its given 1kg = 9x10^16J

so need to figure out the total mass loss n u can find the energy released

mass loss when 4x H atom combines to form 1x He atom in a fusion reaction is given as 4.59x10^-29kg

1 mole of He has 6.02x10^23 He atoms

so 2.7 moles of He has 2.7x6.02x10^23 He atoms

the total mass loss for 2.7 moles of He created in a fusion reaction

= 2.7x6.02x10^23 x 4.59x10^-29kg

= 7.46x10^-5kg

radiation energy released from this fusion reaction

= 7.46x10^-5 x 9x10^16J

= 6.7x10^12J

its 60 BILLION times more than burning carbon!!

7 0

3 years ago

Read 2 more answers

One end of a horizontal spring with force constant 76.0 N/m is attached to a vertical post. A 5.00-kg can of beans is attached t

Jobisdone [24]

Answer:

a. The speed is 2.39 m/s

b. The acceleration of the block is 10.2 $\frac{m}{s^{2} }$

Explanation:

First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:

$K_{1} +U_{1}+W_{ext}=K_{2}+U_{2}\\K_{1}=0\\U_{1}=\frac{1}{2} kx^{2} _{1} =0\\W_{ext}=F$ Δx= $(0.400m)\\$

W_{ext}=20.4 Nm

$U_{2} =\frac{1}{2} kx^{2} =\frac{1}{2} (76.0N/m)0.400^{2}=6.08Nm\\k_{2} =\frac{1}{2}mv^{2} _{2} \\\frac{1}{2} mv^{2} _{2}=W_{ext}-U_{2}\\v_{2}=\sqrt{\frac{W_{ext}-U_{2}}{m} } \\v_{2}=\sqrt{\frac{20.4Nm-6.08Nm}{2.5kg} } \\v_{2}=2.39 \frac{m}{s}$

To determine, the acceleration we solve the following equation for a:

$F=ma\\a=\frac{F}{m} =\frac{51.0N}{5.00kg}\\a=10.2\frac{m}{s^{2} }$

8 0

4 years ago