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anyanavicka [17]
3 years ago
7

What happens to the atomic number of an atom when the number of neutrons in the nucleus of that atom increases?

Physics
1 answer:
Contact [7]3 years ago
6 0

Answer:

It remains the same

Explanation:

Atomic number is the number of protons in a nucleus so no effect due to change of neutrons.

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Which chemical reaction is the fastest?
Lina20 [59]

Answer:

D. Baking soda produces bubbles when vinegar is poured on it.

Explanation:

Acetic acid = C₂H₄O₂

Baking soda = NaHCO₃

C₂H₄O₂ + NaHCO₃ → NaC₂H₃O₂ + H₂O + CO₂

When baking soda is added to vinegar, a chemical reaction will take place producing a huge amount of carbon-dioxide in the form of bubbles in the foaming mixture.

4 0
3 years ago
The fundamental frequency of a pipe that is open at both ends is 564 hz . part a how long is this pipe?
Len [333]
I hope this will be helpful i made a bold assumption of speed of sound since it is not provided

6 0
3 years ago
Read 2 more answers
An electron in the highest occupied energy level of an atom is called
svet-max [94.6K]

Answer:

valence

Explanation:

7 0
3 years ago
A spring has a spring constant of 113 N/m . How much elastic potential energy is stored in the spring when it is compressed by 0
andrezito [222]

Answer:

= 1.7 Joules

Explanation:

The electrical potential energy is given by;

P.E = 1/2 ke²

Where, k is the spring constant, e is the extension

Therefore;

Electrical potential energy = 1/2 × 113 N/m × 0.03 m

                                           =  1.695 Joules

                                           <u>= 1.7 J</u>

7 0
3 years ago
Read 2 more answers
A steel ball with mass m is suspended from the ceiling at the bottom end of a light, 17.0-m-long rope. The ball swings back and
iogann1982 [59]

Answer:

1. 18.25 m/s

2. 0 m/s

Explanation:

1.So the centripetal acceleration of the ball at this lowest point must be, taking gravity into account

a_c = \frac{T - mg}{m} = \frac{3mg - mg}{m} = 2g

The speed at this point would then be

v^2 = a_c r = 2gr = 2*9.8*17 = 333.2

v = \sqrt{333.2} = 18.25 m/s

2. Similarly, if T = mg, then the centripetal acceleration must be

a_c = \frac{T - mg}{m} = \frac{mg - mg}{m} = 0

As the ball has no centripetal acceleration, its speed must also be 0 as well.

6 0
4 years ago
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