All categories

3 years ago

This does not make sense even when I put 4321 it still did not work

Mathematics

1 answer:

ella [17]3 years ago

3 0

Answer:

Maybe you should refresh your page if you can.

You might be interested in

What is the length of the missing leg?

sp2606 [1]

Answer:

$a=12$

Step-by-step explanation:

Pythagorean Theorem: $a^{2}+b^{2}=c^{2}$

In this case, a = 9, b = a, and c = 15.

$9^{2}+a^{2}=15^{2}$

$81+a^{2}=225$

The, we subtract 81 from both sides getting:

$a^{2}=144$ ,

Then, $a=12$

6 0

2 years ago

Is the relation a function? {(14, 15), (5, 7), (3, 10), (11, 1), (5, 8)} a. yes. b. no

Monica [59]

In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 : f ( x ) = 7 and also for x = 5, f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.

8 0

3 years ago

Use the Euclidean Algorithm to find the greatest common divisor of the polynomials f(x) = x^3 + 3x^2 + 6x + 1 and g(x) = 5x^4 +

fomenos

Answer:

3x+1.

Step-by-step explanation:

First we divide g(x)/f(x) (the process is in the first image):

5x-15 in Z7[x] is 5x-1 and $17x^2+86x+16$ is $r(x)= 3x^2+2x+2$ in Z7[x]. So

g(x)/f(x) = $(5x-1)(x^3+3x^2+6x+1)+3x^2+2x+2$

Now gcd(g,f) = gcm(f,r).

f(x)/r(x) = $5x(3x^2+2x+2) + 3x+1$

Then, gcd(f,r) = gcd(r,3x+1).

r/(3x+1) = $(x+5)(3x+1) +4$

Then, gcd(r, 3x+1) = gcd(3x+1,4) = 3x+1.

So, gcd(f,g) = 3x+1.

5 0

3 years ago

How to simplify fractions

REY [17]

$\frac{1}{2}+\frac{1}{4}$ You have to make the denominators(bottom of the fraction) the same in order to combine the fractions.

To make the denominator of $\frac{1}{2}$ the same as $\frac{1}{4}$ , you multiply the top and bottom of the fraction by 2 (because they both have a common multiple of 4)

$\frac{1*2}{2*2}=\frac{2}{4}$

So:

$\frac{2}{4} +\frac{1}{4} =\frac{3}{4}$

7 0

2 years ago

Read 2 more answers

32 = 1.69 is this correct

ddd [48]

Yes this is correct answer

3 0

2 years ago