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KiRa [710]
3 years ago
5

Can someone please answer this !?!!

Mathematics
2 answers:
Olenka [21]3 years ago
5 0

Answer:

Midpoint

Step-by-step explanation:

It is in the center of where the two axis' meet.

snow_tiger [21]3 years ago
4 0

Answer:

midpoint is the answer.....

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Help please<br><br> 1 1/2% of what number is 10.05
MrRissso [65]

Answer:

10/25%

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The assets division should contain what accounts
fredd [130]

98610100Using your completed Chart of Accounts, choose the one correct answer.1. The assets division should contain what accounts?A. 11 P.Woodsley, Capital12 Equipment—Store13 Equipment—Office14 Cash15 Accounts Payable—Taylor InvestmentsB. 11 Accounts Payable—Bellhaven Bank12 Equipment—Store13 Equipment—Office14 P.Woodsley, Capital15 CashC. 11 Cash12 Equipment—Store13 Equipment—Office14 Prepaid Insurance15 Accounts Payable—Taylor InvestmentsD. 11 Cash12 Prepaid Insurance13 Equipment—Store14 Equipment—Office15 Supplies2. The liabilities division should contain what accounts?A. 21 Accounts Payable—Bellhaven Bank22 P.Woodsley—CapitalB. 21 Accounts Payable—Bellhaven Bank22 Accounts Payable—Taylor InvestmentsC. 2122D. 21 Accounts Payable—Bellhaven Bank22 Merchant’s Bank3. The owner’s equity division should contain what account(s)?A. 31 P.Woodsley—Capital




4 0
3 years ago
Which measure of center will provide the most accurate estimation of the deposits for the savings account? Why?
faust18 [17]
Hello,

First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.

Afterwards you have to find the median. Why ?

I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.

"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
Furthermore, here there are 3 numbers which appears the most ( 2 times for each) : $85, $95 and $100. Which one will you take ?

Therefore the median is the most suitable and the most accurate to know the center because it is robust.

Now, let's find the median :

There are 10 values, so the median will be the average of the 5th and 6th values.

5th value = 85
6th value = 95

\frac{(85+95)}{2}
= 90

Therefore the median is 90.

Hope this helps !

Photon
4 0
3 years ago
All of them I need help please
NemiM [27]
19. 

2568.75 - 2500 = 68.75;

( ? / 100 ) * 2500 = 68.75 ;

? * 25 = 68.75;

? = 68.75 ÷ 25

? = 2.75;

r = 2.75 %
7 0
2 years ago
P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
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