Can someone please answer this !?!!
2 answers:
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Hello,
First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.
Afterwards you have to find the median. Why ?
I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.
"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
Furthermore, here there are 3 numbers which appears the most ( 2 times for each) : $85, $95 and $100. Which one will you take ?
Therefore the median is the most suitable and the most accurate to know the center because it is robust.
Now, let's find the median :
There are 10 values, so the median will be the average of the 5th and 6th values.
5th value = 85
6th value = 95
Therefore the median is 90.
Hope this helps !
Photon
First you have order all the number least to the greater. That gives 30, 75, 80, 85, 85, 95, 95, 100, 100, 110.
Afterwards you have to find the median. Why ?
I will explain you. It's because the median is robust. In fact, it can't be influenced by extreme values (example : 110) but the mean yes. So the mean won't be accurate.
"Then why don't you choose the mode ? " you will ask me. That's because the mode takes the number which appears most often in a set of numbers. It couldn't be accurate at all. It will be useless for this set of numbers.
Furthermore, here there are 3 numbers which appears the most ( 2 times for each) : $85, $95 and $100. Which one will you take ?
Therefore the median is the most suitable and the most accurate to know the center because it is robust.
Now, let's find the median :
There are 10 values, so the median will be the average of the 5th and 6th values.
5th value = 85
6th value = 95
Therefore the median is 90.
Hope this helps !
Photon
Answer:
19.49% probability that no more than 16 of them are strikes
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that ,
.
In this problem, we have that:
So
What is the probability that no more than 16 of them are strikes?
Using continuity correction, this is , which is the pvalue of Z when X = 16.5. So
has a pvalue of 0.1949
19.49% probability that no more than 16 of them are strikes