<span>Let the width of the rectangular plot of land be 'x' yards.
Given that the length of the rectangular plot of land is 10 yards more than its width.
So, width of the rectangular plot of land = (x + 10) yards.
Also given that the area of the rectangular plot of land is 600 square yards.
We know that, area of a rectangle = length * width
That is, (x+10) * x = 600
x^2 + 10x = 600
x^2 + 10x - 600 = 0
x^2 + 30x - 20x -600 = 0
x(x + 30) - 20(x + 30) = 0
(x +30)(x -20) =0
Therefore, either (x + 30) = 0 or (x - 20) = 0
If x + 30 = 0, then x = -30 and
If x - 20 = 0, then x = 20
Since 'x' represents the width of a rectangular plot of land it cannot be negative.
Therefore,
width of the rectangular plot of land = 20 yards
length of the rectangular plot of land= x + 10 = 30 yards</span>
Answer:
D
Step-by-step explanation:
Answer:
x = -3 +/- square root(22)
Step-by-step explanation:
x = -b +/- square root(b^2 - 4ac) / 2a
ax^2 + bx + c = 0
these are both the quadratic formula but one is solved for the x and another for 0
a= 1
b= 6
c = -13
x= -6 +/- square root( 6^2 - 4(1)(13)) / 2(1)
x = -6 +/- sqrt( 36 + 52) / 2
x= -6 +/- sqrt (88) / 2
sqrt of 88 = 2 x sqrt (22)
divide 2 on each
x= -3 +/- sqrt (22)
For this question the answer is -3/2
The absolute value of zero is zero
