The answer to your problem is -1x.
Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
Answer:
the answer is A I think it will help u
Flower bed A:
circumference= 2 x pi x r= 2x pi x10/2
=10pi feet
Area= pi x r^2=25pi square feet
Flower bed B:
circumference=12 pi feet
Area=36 pi square feet