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marysya [2.9K]
3 years ago
10

What is 12.38 in word form

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0
it will be twelve and thirty eight hundredths
marishachu [46]3 years ago
3 0
12.38 in word form: Twelve and thirty-eight hundreths
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5x^2+11x=0 quadratic equation
hammer [34]
5x^{2} + 11x = 0

5x^{2} + 11x + 0 = 0
x = \frac{-(11) +/- \sqrt{(11)^{2} - 4(5)(0)}}{2(5)}

x = \frac{-11 +/- \sqrt{121 - 0}}{10}

x = \frac{-11 +/- \sqrt{121}}{10}

x = \frac{-11 +/- 11}{10}

x = \frac{11 + 11}{10}         x = \frac{11 - 11}{10}

x = \frac{22}{10}               x = \frac{0}{10}

x = 2.2              x = 0
3 0
3 years ago
Hurry Timed!!! PLEASE ANSWER
Marizza181 [45]

Answer:

480

Step-by-step explanation:

time all of them

4 0
2 years ago
2 points
natima [27]

Answer:

4.9 feet

Step-by-step explanation:

First, we need to determine the height of the building using the following:

L^2 = H^2 + B^2

Where

H = Height of the building

L = Length of the first ladder = 20ft

B = Distance from the base of the building = 10ft

So, we have:

20^2 = H^2 + 10^2

400 = H^2 + 100

H^2 = 400 - 100

H^2 = 300

H = \sqrt{300

Next, is to determine the distance of the new ladder from the base of the building (B) using Pythagoras theorem using:

L_2^2 = H^2 + B_2^2

Where

L_2 = 18 --- Length of the second ladder

H = \sqrt{300 ----- Height of the building

So, we have:

18^2 = \sqrt{300}^2 + B_2^2

324 = 300 + B_2^2

B^2_2 = 324 - 300

B^2_2 = 24

Solving for B2, we have:

B_2 = \sqrt{24

B_2 = 4.9

8 0
3 years ago
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
3 years ago
In a 24 marathon, solve the 24 puzzle given by the poster above you, and post a new 24 puzzle of your own!
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7 0
1 year ago
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