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OLEGan [10]
3 years ago
5

Which of the following is a way that materials are used?

Chemistry
1 answer:
Svetach [21]3 years ago
8 0

Answer:

the answer is B.Construction

Explanation:

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In a sample of oxygen gas at room temperature, the average kinetic energy of all the balls stays constant. Which postulate of ki
Levart [38]

Answer:

Collisions between gas particles are elastic; there is no net gain or loss of kinetic energy.

Explanation:

When a gas is paced in a container, the molecules of the gas have little or no intermolecular interaction between them. There is a lot of space between the molecules of the gas.

The gas molecules move at very high speed and collide with each other and with the walls of container.

The collision of these particles with each other is perfectly elastic hence the kinetic energy of the colliding gas particles do not change.

7 0
3 years ago
QUESTION 7
Lera25 [3.4K]
Answer:
it’s quite simple.
The newton force in a aerodynamic space which could lead to a catastrophic entanglement will be added to the physical quantum molecular structure then subtracted by its opposite, inter dimensional indispensable aerobic activity, then finally multiplied by the sum which was subtracted by the addition to then divide the sum of it all with the solution of the multiplication which would equal to the answer.
4 0
2 years ago
Which compound is bonded covalently? A.KF B.MgS C.BeO D.SO2
Masja [62]

Answer:

SO2 is bonded covalently

Explanation:

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6 0
2 years ago
What equipment might you use to find the SHC of a material? Need to know the answer ASAP PLZ
algol [13]
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4 0
3 years ago
A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a
Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of CH_3C0_2 H= 77 \ g \\\\

Molar mass of CH_3C0_2 H = 60.05 \  \frac{g}{mol} \\\\

No of moles in n_{CH_3CO_2H} = 77 \ g \times  \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}  

                                          = 1.28 \ mol \ CH_3CO_2H

Mass of water (H_2O)= 42 \ g

The molar mass of water (H_2O)= 18.02 \  \frac{g}{mol}

moles of water n_{H_2O}:

= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O

Molfraction of acetic acid:

X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\

                     =\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35

7 0
2 years ago
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