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Vaselesa [24]
3 years ago
13

Suppose you had 2.0158 grams of (H2) how many moles of hydrogen do u have ?

Chemistry
1 answer:
ale4655 [162]3 years ago
7 0
\hbox { You have to calculate the Molecular Mass for H2:}

M_{H2} = 2A _{H2} = 2*1=2 \hbox { grames/mole}

\hbox { So, in 2,0158 grames of H you will have 1 mole...}
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Evidence for evolution reveals that closely related organisms have many (blank)<br>characteristics.​
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Evidence for evolution reveals that closely related organisms have many similar  physical and genetic characteristics.

Explanation:

Closely related organisms have similar physical features and genetic sequences.

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You need 270 ml of a 65% alcohol solution. on hand, you have a 90% alcohol mixture. how much of the 90% alcohol mixture and pure
olganol [36]

You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

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4 years ago
What happens in this circuit if one of the light bulbs burns out?
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3 years ago
La masa de una olla es de 300g y contiene 90% de aluminio. Hallar el número de moles de aluminio de la olla. P.A.(Al= 27)
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Explanation:

The mass of a pot is 300g and contains 90% aluminum. Find the number of moles of aluminum in the pot. P.A. (Al = 27)

The mass of aluminum present in the pot is:

300 g * 90/100\\=270 g

Hence, in the given pot 270g Al is present.

Number of moles of Al=\frac{given mass ofAl}{its molar mass}

The gram atomic mass of Al -27 g/mol

Given the mass of Al is 270 g

Substitute these values in the above formula:

Number of moles of Al=\frac{given mass ofAl}{its molar mass}\\=\frac{270 g}{27 g} \\=10.0 mol

Answer is 10.0 mol of Al is present.

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3 years ago
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