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tia_tia [17]
3 years ago
13

Malik analyzed three samples to test which element was a metalloid. The table shows his results. Which element (A, B, or C) is m

ost likely a metalloid?

Chemistry
2 answers:
11111nata11111 [884]3 years ago
7 0

the answer is c :)

have a good day (good vibes only)

- sav <3

MatroZZZ [7]3 years ago
4 0
<h2>Answer : C</h2><h3>Explanation :</h3>

According to the test results obtained by Malik it is clear that C is the element which can be classified as a metalloid. As it has all the features of metalloid.

It is lustrous and brittle. It can either react like and acid or base. It has sharp melting point and main identity was that it has medium electrical conductivity.

This all signs prove that it is a metalloid in nature.

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A student dissolves 15.0 g of ammonium chloride(NH4Cl) in 250. 0 g of water in a well-insulated open cup. She then observes the
iren2701 [21]

Answer:  

1) Endothermic.  

2) Q_{rxn}=4435.04J  

3) \Delta _rH=15.8kJ/mol

Explanation:  

Hello there!  

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.  

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

Q_{rxn}=-(15.0g+250.0g)*4.184\frac{J}{g\°C}(16.0-20.0)\°C\\\\ Q_{rxn}=4435.04J    

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol

Best regards!  

Best regards!

4 0
3 years ago
H+ is protium,deuterium and tritium?
MrRissso [65]
H⁺ is the nucleus of protium
___________________________________________
8 0
3 years ago
What is the concentration in molarity of a solution that has 54.21g of calcium hydroxide dissolved in 560mL of water?
ra1l [238]
We know that Molarity = # mol/L

In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is: Ca(OH)_{2

This means that we have 1 calcium and 2 hydroxides.

We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:

Ca = 40.08g
O = 15.999g
H = 1.008g

We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:

40.08 + 2(15.999) + 2(1.008) = 74.094g

Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:

54.21g/74.09g = 0.73 moles of Ca(OH)_{2}

Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L

Knowing all of this information, we can plug it into the molarity equation:

Molarity = 0.73 mol/0.56 L
Molarity = 1.30

The molarity of the solution is 1.3 M.
4 0
3 years ago
9. What is useful in constructing scientific questions, methods, and explanations?
Varvara68 [4.7K]

Answer: C

creativity

Explanation:

C. Because the results of some experiments might not be explained by any

known theories.

3 0
3 years ago
DH
viva [34]

a. 4- bromocyclohexanol is an acidic proton

b. Benzenesulfonic acid deactivates the entire process

c. (2S, 3R)-2,3-Dibromobutane are racemic mixtures

d.  Williamson synthesis cannot be used with tertiary alkyl halides

e. Nucleophiles are not involved in the rate determining step

<h3>The reasons that might help to explain the following observations are:</h3>

a. Grignard reagents cannot be made if acidic functional groups are also present in the halogen compound and it is also destroyed by reaction with acidic hydrogen atoms of water, alcohols, phenols, or carboxylic acid groups.

4-bromocyclohexanol is an acidic proton compound

b. Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because the carboxylic group causes deactivation, carboxylic group and the Lewis acid catalyst are also bonded in the process.

c. (2S, 3R)-2,3-Dibromobutane has a specific rotation, [a]o, of 0° are racemic mixtures having equal and opposite specific rotations and a racemic mixture has a specific rotation of zero (0°)

d. This is because the Williamson synthesis cannot be used with tertiary alkyl halides which in this case is t-butyl bromide because they undergo elimination reactions instead of participating in SN2 reactions and form alkenes instead of ethers.

e. Doubling the concentration of a nucleophile has no effect on the rate of a substitution reaction because the nucleophile is not involved in the rate-determining step of the SN-1 reaction.

Learn more about organic reactions here:

brainly.com/question/3529377

#SPJ1

5 0
3 years ago
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