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krek1111 [17]
3 years ago
12

What is the concentration in molarity of a solution that has 54.21g of calcium hydroxide dissolved in 560mL of water?

Chemistry
1 answer:
ra1l [238]3 years ago
4 0
We know that Molarity = # mol/L

In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is: Ca(OH)_{2

This means that we have 1 calcium and 2 hydroxides.

We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:

Ca = 40.08g
O = 15.999g
H = 1.008g

We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:

40.08 + 2(15.999) + 2(1.008) = 74.094g

Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:

54.21g/74.09g = 0.73 moles of Ca(OH)_{2}

Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L

Knowing all of this information, we can plug it into the molarity equation:

Molarity = 0.73 mol/0.56 L
Molarity = 1.30

The molarity of the solution is 1.3 M.
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What is the mass, in grams, of
DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2   MW = 32 + 2 = 34 g

                                    34g -------------------- 6.023 x 10²³ molecules

                                    x       -------------------  6.85 x 10 ²⁰

                                   x = (6.85 x 10 ²⁰)(34)/  6.023 x 10²³

                                   x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

                                    64 g -------------------- 6.023 x 10²³ molecules

                                    x      --------------------  3.3×1022 SO2 molecules

                                    x = (3.3×1022 SO2)(64) / 6.023 x 10²³

                                   x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

                                 48 g -----------------   6.023 x 10²³ molecules

                                  x     ------------------   5.5×1025 O3 molecules

                               x = (5.5×1025 )(48) /  6.023 x 10²³

                               x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

                              16 g --------------------  6.023 x 10²³ molecules

                              x      --------------------   9.30×1019 CH4 molecules

                           x = (9.30×1019)(16) / 6.023 x 10²³

                           x = 0.0025 g

4 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
4 years ago
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The condensed formula would be CH3-CH(CH4)-CH2-CH(CH4)-CH2-CH(CH4)-CH3. The molecular formula would be C10H25.
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