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skad [1K]
2 years ago
12

DH

Chemistry
1 answer:
viva [34]2 years ago
5 0

a. 4- bromocyclohexanol is an acidic proton

b. Benzenesulfonic acid deactivates the entire process

c. (2S, 3R)-2,3-Dibromobutane are racemic mixtures

d.  Williamson synthesis cannot be used with tertiary alkyl halides

e. Nucleophiles are not involved in the rate determining step

<h3>The reasons that might help to explain the following observations are:</h3>

a. Grignard reagents cannot be made if acidic functional groups are also present in the halogen compound and it is also destroyed by reaction with acidic hydrogen atoms of water, alcohols, phenols, or carboxylic acid groups.

4-bromocyclohexanol is an acidic proton compound

b. Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because the carboxylic group causes deactivation, carboxylic group and the Lewis acid catalyst are also bonded in the process.

c. (2S, 3R)-2,3-Dibromobutane has a specific rotation, [a]o, of 0° are racemic mixtures having equal and opposite specific rotations and a racemic mixture has a specific rotation of zero (0°)

d. This is because the Williamson synthesis cannot be used with tertiary alkyl halides which in this case is t-butyl bromide because they undergo elimination reactions instead of participating in SN2 reactions and form alkenes instead of ethers.

e. Doubling the concentration of a nucleophile has no effect on the rate of a substitution reaction because the nucleophile is not involved in the rate-determining step of the SN-1 reaction.

Learn more about organic reactions here:

brainly.com/question/3529377

#SPJ1

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Explanation:

3 0
3 years ago
The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri
levacccp [35]

<u>Answer:</u> The equilibrium concentration of HCl is 2.26\times 10^{-3}M

<u>Explanation:</u>

We are given:

Moles of NH_4Cl(s) = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Molarity of NH_4Cl=\frac{0.564}{1}=0.564M

The given chemical equation follows:

                  NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)

<u>Initial:</u>         0.564

<u>At eqllm:</u>     0.564-x          x              x

The expression of K_c for above equation follows:

K_c=[NH_3][HCl]

The concentration of pure solid and pure liquid is taken as 1.

We are given:

K_c=5.10\times 10^{-6}

Putting values in above equation, we get:

5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M

Negative sign is neglected because concentration cannot be negative.

So, [HCl]=2.26\times 10^{-3}M

Hence, the equilibrium concentration of HCl is 2.26\times 10^{-3}M

5 0
3 years ago
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Explanation:

3 0
3 years ago
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the answer is 8 electrons

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