1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skad [1K]
2 years ago
12

DH

Chemistry
1 answer:
viva [34]2 years ago
5 0

a. 4- bromocyclohexanol is an acidic proton

b. Benzenesulfonic acid deactivates the entire process

c. (2S, 3R)-2,3-Dibromobutane are racemic mixtures

d.  Williamson synthesis cannot be used with tertiary alkyl halides

e. Nucleophiles are not involved in the rate determining step

<h3>The reasons that might help to explain the following observations are:</h3>

a. Grignard reagents cannot be made if acidic functional groups are also present in the halogen compound and it is also destroyed by reaction with acidic hydrogen atoms of water, alcohols, phenols, or carboxylic acid groups.

4-bromocyclohexanol is an acidic proton compound

b. Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because the carboxylic group causes deactivation, carboxylic group and the Lewis acid catalyst are also bonded in the process.

c. (2S, 3R)-2,3-Dibromobutane has a specific rotation, [a]o, of 0° are racemic mixtures having equal and opposite specific rotations and a racemic mixture has a specific rotation of zero (0°)

d. This is because the Williamson synthesis cannot be used with tertiary alkyl halides which in this case is t-butyl bromide because they undergo elimination reactions instead of participating in SN2 reactions and form alkenes instead of ethers.

e. Doubling the concentration of a nucleophile has no effect on the rate of a substitution reaction because the nucleophile is not involved in the rate-determining step of the SN-1 reaction.

Learn more about organic reactions here:

brainly.com/question/3529377

#SPJ1

You might be interested in
In a chromatography experiment, chlorophyll pigments are separated using paper. What is the stationary phase in this experiment?
Bond [772]
Answer:
The stationary phase in chromatography experiment is paper.

Explanation:
In chromatography experiment, the stationary phase is defined as the fixed substance that is necessary to start chromatography. In our case, this fixed substance is paper, so that makes paper our stationary phase.

Hope this helps :)
4 0
3 years ago
Read 2 more answers
Select all of the items that are true about a sample of water vapor at 101°C as it cools.
Dvinal [7]
<h3><u>Answer;</u></h3>

A) Its temperature will fall continuously until it condensed into a liquid.

<h3><u>Explanation</u>;</h3>
  • <em><u>Steam or water vapor is the gaseous state of liquid water.  When water vapor above a temperature of 100 degrees Celsius is cooled, the temperature falls continuously, and it undergoes condensation at a temperature of 100 degrees Celsius and turns into liquid water.</u></em>
  • The change of state from gaseous to liquid state occurs as a result of latent heat of vaporization that the water vapor carries.
4 0
3 years ago
Read 2 more answers
What is the molar mass of CaCl2?
alekssr [168]
Molar mass of CaCl2 = 40+ ( 35.5 ×2)=110

Mr of Ca(OH)2 = 40+ (16+1)×2 =74

%of Ca = (40÷ 74)×10=...

1 m = 100cm...
1cm = (1÷100) m
So 45.5 cm = 45.5 ×(1÷100) =....

1km = 1000m
1m = 100 cm
1cm =10mm
So 1km = 1000×100×10 mm
Now convert
7 0
3 years ago
Someone help me please ​
kow [346]
1)Straight chain hydrocarbons are named according to the number of carbon atoms: CH4, methane; C2H6 or H3C-CH3, ethane; C3H8 or H3C-CH2-CH3, propane; C4H10 or H3C-CH2- CH2-CH3, butane; C5H12 or CH3CH2CH2CH2CH3, pentane; C6H14 or CH3(CH2)4CH3, hexane; C7H16, heptane; C8H18, octane; C9H20, nonane; C10H22, CH3(CH2)8CH3, ..
5 0
2 years ago
2C4H10(g) +13O2(g) → 8CO2(g) +10H2O(g) Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighte
MatroZZZ [7]
Answer is: mass of butane is D)11.6 g.
m(butane) = 50,0 g.
V(CO₂) = 17,9 L.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 17,9 L ÷ 22,4 L/mol.
n(CO₂) = 0,8 mol.
From chemical reaction n(CO₂) : n(C₄H₁₀) = 8 : 2.
n(C₄H₁₀) = 0,8 mol ÷ 4.
n(C₄H₁₀) = 0,2 mol.
m(C₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).
m(C₄H₁₀) = 0,2 mol · 58 g/mol.
m(C₄H₁₀) = 11,6 g.
8 0
3 years ago
Other questions:
  • Express your views on how the law, the citizens and community can protect and support victims of human rights violations
    15·1 answer
  • The mass of h2 produced by reaction of 1.80 g al and 6.00 g h2so4 is 0.112 g. what is the percent yield?
    10·1 answer
  • Do you think human activity is responsible for global warming
    10·1 answer
  • Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20C to 30C
    13·1 answer
  • 13 Compared to the physical and chemical properties of the compound NO2 the compound N2O has(1) different physical properties an
    5·1 answer
  • What’s the equation to solid calcium oxide reacts with hydrochloric acid to form a solution of calcium chloride and water as it’
    6·1 answer
  • What does the number of protons<br> determine?
    7·1 answer
  • HELP!!! What two volume units have the same value?
    12·2 answers
  • You are a forensic scientist who has been asked to test two blood samples. You know that one sample is suspected of containing b
    8·1 answer
  • 42,000 mL is equal to L
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!