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Sever21 [200]
3 years ago
15

what would be the ph of an aqueous solution of sulphuric acid which is 5×10^_5 mol l^_1 in concentration​

Chemistry
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

the ph of an aqueous solution of sulphuric acid which is 5*10^5 mol in concentration is basic in nature

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a) Diamond and graphite are two different forms of pure elemental carbon with densities of 3.51 g/cc and 2.25 g/cc respectively.
dybincka [34]
Density can be calculated using the following rule:
density = mass / volume
Therefore,
volume = mass / density

For diamond:
we have mass = 0.5 grams and density = 3.51 g / cm^3
Substituting in the rule, we can calculate the volume of diamond as follows:
volume = 0.5 / 3.51 = 0.14245 cm^3

For graphite:
we have mass = 0.5 grams and density = 2.25 g / cm^3
Substituting in the rule, we can calculate the volume of graphite as follows:
volume = 0.5 / 2.25 = 0.2223 cm^3
8 0
3 years ago
How does rhenium apply to real life​
riadik2000 [5.3K]

Answer: Rhenium is used as an additive to tungsten- and molybdenum-based alloys to give useful properties. These alloys are used for oven filaments and x-ray machines. It is also used as an electrical contact material as it resists wear and withstands arc corrosion.

Explanation:

4 0
3 years ago
Why is the atom neutrally charged?
V125BC [204]
Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged).
3 0
3 years ago
Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ
Ahat [919]

<u>Answer:</u> The Gibbs free energy of the reaction is 21.32 kJ/mol

<u>Explanation:</u>

The chemical equation follows:

\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = 37^oC=[273+37]K=310K

K_{eq} = Ratio of concentration of products and reactants = \frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}

\text{[Oxaloacetate]}=0.130mM

[NADH]=2.0\times 10^2mM

\text{[Malate]}=1.37mM

[NAD^+]=490mM

Putting values in above expression, we get:

\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0
3 years ago
Unit Test
guajiro [1.7K]

Answer:

Heat flows from faster molecules to slower molecules when they collide.

Explanation:

logics

8 0
3 years ago
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