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Maurinko [17]
3 years ago
9

If your vessel is engaged in diving activity during the day, you must exhibit a diver-down flag along with what other rigid flag

to show restricted maneuverability?
Physics
1 answer:
strojnjashka [21]3 years ago
5 0
The navigation rules entail vessels restricted in their ability to maneuver to display appropriate flag or lights. During the day of engagement of vessel in diving activities the rigid replica of the international code flag "ALPHA" must be exhibit not less than 3.3 feet while during night time the vessel must display the navigation light which is red and white and this requirement does not affect divers red and white flag which may be required by state to mark a divers location. The "A" flag is a kind of navigational signal which indicates the vessel’s restricted maneuverability and do not pertain to diver.
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What three sprites are needed to create the Space Invaders game that was discussed in the unit? spaceship, laser, enemy gnome, a
Lilit [14]

Answer: anlien, enemy gnome, spaceship

Explanation:

3 0
2 years ago
A racing car is travelling at 70 m/s and accelerates at -14 m/s2. What would the car’s speed be after 3 s?
Leno4ka [110]
<h3><u>Question</u><u>:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?

<h3><u>Statement:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.

<h3><u>Solution</u><u>:</u></h3>
  • Initial velocity (u) = 70 m/s
  • Acceleration (a) = -14 m/s^2
  • Time (t) = 3 s
  • Let the velocity of the car after 3 s be v m/s
  • By using the formula,

v = u + at, we have

v = 70 + ( - 14)(3) \\  =  > v = 70 - 42 \\  =  > v = 28

  • So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>

The car's speed after 3 s is 28 m/s.

Hope it helps

3 0
3 years ago
A bike race against the clock takes place on a straight road. Yan drives at 37 km / h and he starts the course 30s before Christ
joja [24]

Given data:

Yan speed;

u_1=37\text{ km/h}

Christopher speed;

u_2=38.9\text{ km/h}

Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.

Part (A)

The distance is given as,

d=ut

Let both Yan and Christophe meet at d distance from the start position. Therefore,

u_1t=u_2(t-30)

Substituting all known values,

\begin{gathered} (37\text{ km/h})t=(38.9\text{ km/h})\times(t-30) \\ \frac{(37\text{ km/h})}{(38.9\text{ km/h})}=\frac{(t-30)}{t} \\ 0.95=1-\frac{30}{t} \\ \frac{30}{t}=1-0.95 \\ \frac{30}{t}=0.05 \\ t=\frac{30}{0.05} \\ t=600\text{ s} \end{gathered}

Therefore, 600 s after Yan's departure Christophe will join him.

Part (B)

The distance is given as,

d=u_1t

Substituting all known values,

\begin{gathered} d=(37\text{ km/h})\times(600\text{ s}) \\ =(37\text{ km/h})\times(600\text{ s})\times(\frac{1\text{ hr}}{3600\text{ s}}) \\ \approx6.17\text{ km} \end{gathered}

Therefore, Christophe joins Yan after 6.17 km from the start.

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1 year ago
Can someone please help me
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They’re at a velocity of 2.0 m/s
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3 years ago
What is the purpose of the article physicists test telepathy in a cheat proof setting?
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I'm guessing that the purpose of the article is to inform the
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3 years ago
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