Https://youtu.be/F_DEsMO_Wq8
hope this helped : )
Answer:
Horizontal component of velocity = 241.61 m/s
Explanation:
Given that,
Velocity of a jetliner is 245 m/s
The vertical component of the plane's velocity is 40.6 m/s, 
We need to find the magnitude of the horizontal component of the plane velocity.
The resultant velocity is given by :

Where,
is the horizontal component of the plane velocity

So, the magnitude of the horizontal component of the plane velocity is 241.61 m/s.
The average distance from the Sun to Neptune is about 2.795 billion miles.
That's roughly 0.00048 of a light year .
We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,

But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.
Answer: Ax=(Vx-Vox)/(T)
Vx=Vox+Ax*T
Solving for Ax in terms of Vx, Vox, T
Vx-Vox=Ax*t
Ax=(Vx-Vox)/(T)
This is saying the acceleration in the x-direction can be found by taking the difference between the finial and initial Velocity in x-direction and dividing it by the Total Time.
Any questions please feel free to ask. Thanks