A racing car is travelling at 70 m/s and accelerates at -14 m/s2. What would the car’s speed be after 3 s?
1 answer:
<h3><u>Question</u><u>:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?
<h3><u>Statement:</u></h3>A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.
<h3><u>Solution</u><u>:</u></h3>- Initial velocity (u) = 70 m/s
- Acceleration (a) = -14 m/s^2
- Time (t) = 3 s
- Let the velocity of the car after 3 s be v m/s
- By using the formula,
v = u + at, we have
- So, the velocity of the car after 3 s is 28 m/s.
The car's speed after 3 s is 28 m/s.
Hope it helps
You might be interested in
Answer:
The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Explanation:
Given that,
Relative speed of stick v= 0.96 c
Speed of light
Proper length of stick = 1 m
We need to calculate the length of the stick
Using formula of length
Put the value into the formula
We need to calculate the time the stick take to move
Using formula of time
Put the value into the formula
Hence, The length of the stick is 0.28 m.
The time the stick take to move is 0.97 ns.
Answer:
Explanation:
From frequency of oscillation
Initially with the suspended string, the above equation is correct for the relation, hence
where k is force constant and m is the mass
When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional
Employing f2/ f1, we have