2÷5=0.4 so by dividing 2 by 5 you would get 0.4
-- The width of the school is ' W '. We don't know what that is yet,
but we're going to find out.
-- We're told that the length is 4 times as much. So the length is ' 4 W '.
-- Perimeter is (2 widths) + (2 lengths).
2 widths = 2 W
2 lengths = 8 W
Perimeter = 10 W
-- We're also told that the perimeter is 55m. That's just what we need.
10 W = 55 m
Divide each side of this equation by 10:
W = 5.5 m
There's the width !
The length of the hall is 4 times as much.
Length = 4 W = 22 m
Answer: 2/5 because I divided by 7/7 to get an equivalent fraction
Step-by-step explanation:
The length of the sky lift is 3.387.05 ft
Step-by-step explanation;
By an online search, i found that the sky lift
rises at an angle of 20.75 degrees.
Then we can think on a triangle rectangle, such
that:
One cathetus is 1200ft, this is the opposite
cathetus to the angle of 20.75°
The length of the ski lift would be the
hypotenuse of this triangle rectangle.
Then we can use the relationship:
Sin(a) = opposite cathetus/hypoteuse.
such that:
a = 20.75°
opposite cathetus=1200ft
then:
sin(20.75°) = 1200ft/hypotenuse
hypotenuse =1200ft/sin(20.759) =3.387.05 ft
The length of the sky lift is 3.387.05 ft
Answer: here is ur answer
Step-by-step explanation: