TRUE/FALSE

Read the scenario and then answer the question.

Dvinal [7]

Elias could be standing on the transform boundary.

Answer: Option 1.

<u>Explanation:</u>

Transform boundaries are places where plates slide sideways past one another. At change limits lithosphere is neither made nor devastated. Many change limits are found on the ocean bottom, where they associate fragments of veering mid-sea edges. California's San Andreas issue is a transform boundary.

Transform boundaries are regions where the Earth's plates move past one another, scouring along the edges. Every one of these three sorts of plate limit has its own specific kind of flaw (or break) along which movement happens. Transforms are strike-slip issues. There is no vertical movement—just horizontal.

6 0

3 years ago

Using the following equation: 3H2SO4+ 2Fe -> Fe2(SO4)3+ 3H2

Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄ + 2Fe → Fe₂(SO₄)₃ + 3H₂

now we will compare the moles reactant with product.

H₂SO₄ : Fe₂(SO₄)₃

3 : 1

15 : 1/3×15 = 5

H₂SO₄ : H₂

3 : 3

15 : 15

Fe : Fe₂(SO₄)₃

2 : 1

13 : 1/2×13 = 6.5

Fe : H₂

2 : 3

13 : 3/2×13 = 19.5

Number of moles of product formed by H₂SO₄ are less thus it will act as limiting reactant.

8 0

3 years ago

For molecules with more than one ionizable groups, such as glycine, which of the following statements is true? For molecules wit

tester [92]

Answer: Option (a) is the correct answer.

Explanation:

The isoelectric point (pI) is actually the pH where a particular amino acid exists as a neutral molecule. This means that if pH equals pI then there will be no electric charge on the molecule.

Therefore, the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

A buffer is composed of a solution of weak acid or base and salt of weak acid/base.So, when pH equals pI then there occurs no net charge. Hence, there will be no existence of conjugate acid-base pair.

Therefore, the statement when the pH is near the pI, the solution is near its maximum buffering ability, is false.

It is known that when pH is less than pI then there will be a net positive charge on the amino acid.

Hence, the statement at a pH near the pI, nearly all the molecules carry a net positive charge, is false.

When pH is greater than pI then amino acid will have a net negative charge. Hence, the statement at a pH near the pI, nearly all the molecules carry a net negative charge, is false.

Thus, we can conclude that out of the given options the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

5 0

3 years ago

If a gas has a volume of 750 mL at 25°c, what would the volume of the gas be at 55°c?

Airida [17]

825.5mL

To find this, use the equation $\frac{V1}{T1}$ = $\frac{V2}{T2}$

Make sure to convert all temperatures in Celsius to Kelvin by adding 273. Once you do that, multiply and divide accordingly to get the final answer of 825.5mL

Hope this helps!

4 0

3 years ago

Read 2 more answers

At high temperatures phosphine (PH_3) dissociates into phosphorus and hydrogen by the following reaction: 4PH3 rightarrow P_4 +

Alex_Xolod [135]

Answer:a)p4=0.75mol

H2=4.5mol

B)PH3=1×10^7mole

P4=0.25×10^7mole

H2=1.5×10^7mole

Time taken for 3mol of phosphine to react is 54 ×10^7s

Explanation:From the balanced chemical equation

4PH3____P4+6H2

From Gay lussac law ,when gases combines

,They do so in a ratio which bear a simple ratio with their products,if gases.

So it means from the equation above

4 mol of PH3 will form 1mol of P4 and 6 mol of H2

Meaning that if 4mol of PH3 gives 1mol of P4

Then 3mol of PH3 will give 1/4 mol or 0.75 mol of P4 .

In the same vein,3mol of PH3 will give 6×3/4 mol of H2= 4.5 Mol of H2

B) molar concentration =mole/volume

Meaning mole=molar concentration ×volume

Molar concentration is given as 5Km/m^3=5000mol/m^3

Volume=2L =2×1000=2000m^3

Nos of moles=5000×2000=10^7moles

So for P4,nos of moles =1/4×10^7=0.25×10^7

ForH2 ,6/4 ×10^7=1.5×10^7 moles

Rate= volume/time

Time taken for reaction will be volume/rate=2000/3.715×10^6

=54×10^7s

5 0

3 years ago