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azamat
4 years ago
15

Which group is more reactive than the alkaline earth metals?

Chemistry
2 answers:
SIZIF [17.4K]4 years ago
8 0

Answer: Alkaline metals(Group 1)

Explanation:

These elements react vigorously with cold water to give hydrogen gas and they have one electron in their outer-most shell which allows them to give electron freely and are good reducing agents.

examples of these elements are:

Hydrogen

Lithium

Sodium

Potassium

Rubidium

Hydrogen is the only gas in group 1.

Vlad [161]4 years ago
5 0

Answer: <em>The </em><em>alkali metals</em><em> reactivity is generally higher than the alkaline earth metals. </em>

Explanation: <em>This makes the alkaline earth metals with their two valence electrons less reactive than alkali metals with their one valence electron.</em>

<u>Alkali metals is ns1 and alkaline earth metals is ns2</u>

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What is the percent composition of N H S O in (NH4)2SO4
Lena [83]

Answer:

The percent composition is 21% N, 6% H, 24% S and 49% O.

Explanation:

1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.

In 1 mole of (NH4)2SO4, there are:

- 2 moles of N.

- 8 moles of H.

- 1 mole of S.

- 4 moles of O.

2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:

- 2 moles of N (14g/mol) = 28g

- 8 moles of H (1g/mol) = 8g

- 1 mole of S (32g/mol) = 32g

- 4 moles of O (16g/mol) = 64g

3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:

\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\  \\  \end{gathered}

In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.

So, the percent composition is 21% N, 6% H, 24% S and 49% O.

8 0
1 year ago
A student mixes a 10.0 mL sample of 1.0 M NaOH with a 10.0 mL sample of 1.0 M HCl in a polystyrene container. The temperature of
ElenaW [278]

Answer:

The experimental value of ΔH is -50 kJ/mol

Explanation:

<u>Step 1: </u>Data given

Volume of 1.0 M NaOH = 10.0 mL = 0.01 L

Volume of 1.0 M HCl = 10.0 mL = 0.01 L

Temperature before mixing = 20 °C

Final temperature = 26 °C

Specific heat of solution = 4.2 J/g°C

Density = 1g/mL

<u>Step 2: </u>Calculate q

q = m*c*ΔT

⇒ with m = the mass

  ⇒ 20.0 mL * 1g/mL = 20 grams

⇒  c = specific heat of solution = 4.2 J/g°C

⇒ ΔT = T2 -T1 = 26 -20 = 6 °C

q = 20g * 4.2 J/g°C * 6°C

q = 504 J

ΔHrxn = -q  ( because it's an exothermic reaction)

ΔHrxn = -504 J

<u>Step 3:</u> Calculate number of moles

Moles = Molarity * volume

Moles = 1M *0.01 L = 0.01 moles

<u>Step 4:</u> Calculate the experimental value of ΔH

ΔHrxn = -504 / 0.01 mol = -50400 J/mol = -50.4 kJ/mol

The experimental value of ΔH is -50 kJ/mol

6 0
4 years ago
What must be known to determine the nature of the salt formed from a weak acid and weak base?
Umnica [9.8K]
D the strength of both acid and base
4 0
3 years ago
How many atoms are in CeCL3
SOVA2 [1]
Molar mass of CeCl3 = 246.475 g/mol

This compound is also known as Cerium(III) Chloride.

Convert grams CeCl3 to moles or moles CeCl3 to grams

Molecular weight calculation:
140.116 + 35.453*3
7 0
4 years ago
Read 2 more answers
A decrease in the concentration of reactants causes the rate of the _____ reaction to slow.
nataly862011 [7]
The correct answer is a Forward reaction to slow.
According to Le Chatelier's principle as the reactant decrease so the reaction should go leftward and this is called backward or reverse reaction so the reverse reaction will be fast to achieve equilibrium and the forward reaction will be slow.
6 0
3 years ago
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