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podryga [215]
2 years ago
12

The mass of a block is 12 g and the volume is 6 ml. Calculate the density of the block.

Chemistry
1 answer:
HACTEHA [7]2 years ago
5 0

Answer:

According to mass and volume,  block density is 2 g/ml

Explanation:

Density is a measure, usually used in physics and chemistry, that relates the mass and volume of a solid or compound.

In general terms, the density is directly proportional to the mass, and inversely proportional to the volume, so increasing the mass will also increase the density.

The formula used to calculate the density is

ρ = \frac{m}{V}

Therefore, according to the mass and density of the block

ρ = \frac{12}{6} = 2g/ml

Being the density of the block equal to 2 g/ml.

<em>The other options are not possible, because the values given do not correspond to the result of the equation.</em>

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A mixture of hydrogen (2.02 g) and chlorine (35.90 g) in a container at 300 K has a total gas pressure of 748 mm Hg. What is the
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The partial atmospheric pressure (atm) of hydrogen in the mixture is 0.59 atm.

<h3>How do we calculate the partial pressure of gas?</h3>

Partial pressure of particular gas will be calculated as:

p = nP, where

  • P = total pressure = 748 mmHg
  • n is the mole fraction which can be calculated as:
  • n = moles of gas / total moles of gas

Moles will be calculated as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of Hydrogen gas = 2.02g / 2.014g/mol = 1 mole

Moles of Chlorine gas = 35.90g / 70.9g/mol = 0.5 mole

Mole fraction of hydrogen = 1 / (1+0.5) = 0.6

Partial pressure of hydrogen = (0.6)(748) = 448.8 mmHg = 0.59 atm

Hence, required partial atmospheric pressure of hydrogen is 0.59 atm.

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3 0
1 year ago
How many moles of oxygen are needed to react with 87 grams of aluminum
labwork [276]

Answer:

2.4 moles of oxygen are needed to react with 87 g of aluminium.

Explanation:

Chemical equation:

4Al(s)  + 3O₂(l)   → 2AlO₃(s)

Given data:

Mass of aluminium = 87 g

Moles of oxygen needed = ?

Solution:

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Number of moles of aluminium= Mass/ molar mass

Number of moles of aluminium= 87 g/ 27 g/mol

Number of moles of aluminium= 3.2 mol

Now we will compare the moles of aluminium with oxygen.

                              Al         :         O₂

                               4          :         3

                               3.2       :         3/4×3.2 = 2.4 mol

2.4 moles of oxygen are needed to react with 87 g of aluminium.

5 0
2 years ago
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Answer:

Explanation:

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∴ Total (internal energy) = 3 + 2 = 5

b) Translational + Rotational + Vibrational = 3 + 2 + 1 = 6

c) Linear molecule  

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ii)  Monatomic molecule

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The less mass in a given volume of air the
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Which is NOT a correct assumption related to the Kinetic Theory?
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Answer:

D

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