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vivado [14]
3 years ago
14

Apply Concepts H2O and H2O2 are binary molecular compounds generally known by their common names, “water” and “hydrogen peroxide

.” Following the naming conventions you identified for molecular compounds, what would their names be? Explain your reasoning.
Chemistry
1 answer:
labwork [276]3 years ago
4 0

Answer:The two-party system came into being because the structure of U.S. elections, with one seat tied to a geographic district, tends to lead to dominance by two major political parties. ... Plurality voting has been justified as the simplest and most cost-effective ... After the election is over, supporters experience remorse when

Explanation: hope u get it right

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What is the answer to this question
kvasek [131]

Answer:

b. double bonds, triple bonds, carbon atoms,and hydrogen atoms.

Explanation:

<h2>please mark me brainliest</h2>
3 0
3 years ago
Please help me I don't know these.
blagie [28]
Add x on all of them I just took what ur taking rn !!!!!
4 0
3 years ago
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If an atom has an electron configuration of 2.8.2, what will it be most likely to bond with?
Kipish [7]

Answer:

B. Two chlorine atoms

Explanation:

This electronic configuration shows that the given atom is magnesium.

Electronic configuration of magnesium:

Mg¹² = 1s² 2s² 2p⁶ 3s²

There are two valance electrons of magnesium that's why it would react with two atoms of chlorine. Chlorine is present in seventeen group. It has seven valance electrons. It required just one electron to get complete octet. While magnesium needed to lose two electrons to get complete octet. That's why two chlorine atoms bonded with one magnesium atom. Thus both would get complete octet.

Mg + Cl₂  →   MgCl₂

3 0
2 years ago
What happens in cellular respiration?
Paha777 [63]

Answer:

Option B

Explanation:

The reaction can be summarized as

6O2+C6H12O6——›6CO2+6H2O+Heat

8 0
2 years ago
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If 0.213 moles of argon occupies a volume of 652 mL at a particular temp and pressure, what volume would it occupy if 0.162 mole
Andreas93 [3]

Answer:

V₂  = 495.89 mL

Explanation:

Given data:

Initial number of moles = 0.213 mol

Initial volume = 652 mL

Final number of moles = 0.162 mol

Final volume = ?

Solution:

V₁/n₁    =    V₂/n₂

By putting values,

652 mL/0.213 mol   =  V₂ /0.162 mol

V₂  = 652 mL 0.162 mol /0.213 mol

V₂  = 105.62 mL.mol /0.213 mol

V₂  = 495.89 mL

3 0
2 years ago
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