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Naddik [55]
3 years ago
10

For molecules with more than one ionizable groups, such as glycine, which of the following statements is true? For molecules wit

h more than one ionizable groups, such as glycine, which of the following statements is true? At pH near the pI, nearly all the molecules carry no net charge. When the pH is near the pI, the solution is near its maximum buffering ability. At a pH near the pI, nearly all the molecules carry a net positive charge. At a pH near the pI, nearly all the molecules carry a net negative charge.ure/courses/32432/files
Chemistry
1 answer:
tester [92]3 years ago
5 0

Answer: Option (a) is the correct answer.

Explanation:

The isoelectric point (pI) is actually the pH where a particular amino acid exists as a neutral molecule. This means that if pH equals pI then there will be no electric charge on the molecule.

Therefore, the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

A buffer is composed of a solution of weak acid or base and salt of weak acid/base.So, when pH equals pI then there occurs no net charge. Hence, there will be no existence of conjugate acid-base pair.

Therefore, the statement when the pH is near the pI, the solution is near its maximum buffering ability, is false.

It is known that when pH is less than pI then there will be a net positive charge on the amino acid.

Hence, the statement at a pH near the pI, nearly all the molecules carry a net positive charge, is false.

When pH is greater than pI then amino acid will have a net negative charge. Hence, the statement at a pH near the pI, nearly all the molecules carry a net negative charge, is false.

Thus, we can conclude that out of the given options the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

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3 0
3 years ago
Find the weight of HNO_3 present in 20ml, 0.30 N
yanalaym [24]

Answer:

mass of HNO₃ = 0.378 g

Explanation:

Normality = Molarity * number of equivalents

Molarity = Normality/number of equivalents

normality of HNO₃ = 0.30 N, Volume = 20 mL

HNO₃ ionizes in the following way:

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mass = 0.006 * 63

mass of HNO₃ = 0.378 g

6 0
3 years ago
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