1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
konstantin123 [22]
3 years ago
5

a basketball is tossed upwards with a speed of 5.0 m/s What is the maximum height reached by the basketball from its release poi

nt?
Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

Maximum height, h = 1.27 meters

Explanation:

It is given that,

Initial speed of the basketball, u = 5 m/s

At maximum height, the final speed of the basketball, v = 0

Let h is the maximum height reached by the basketball from its release point. It can be calculated using third equation of motion as :

v^2-u^2=2as

Here, a = -g

-u^2=-2gh

u^2=2gh

h=\dfrac{u^2}{2g}

h=\dfrac{(5)^2}{2\times 9.8}

h = 1.27 meters

So, the maximum height reached by the basketball from its release point is 1.27 meters. Hence, this is the required solution.

den301095 [7]3 years ago
3 0

Answer:

1.275 m

Explanation:

Let the maximum height reached be h.

Here initial velocity, u = 5 m/s

Final velocity, V = 0

Use third equation of motion

V^2 = u^2 + 2 g h

0 = 25 - 2 × 9.8 × h

h = 25/19.6 = 1.275 m

You might be interested in
For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
slava [35]

Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

5 0
3 years ago
10) T F Two unequal weights are connected by a massless string which passes over a frictionless pulley. If the pulley has no app
neonofarm [45]

Answer:

2

Explanation:

2

3 0
3 years ago
Read 2 more answers
Can someone help me find the answer?
Nikitich [7]
Brown black fur and medium tail
8 0
3 years ago
The slope of a distance-time graph will give
Dafna1 [17]
5.
explanation: the answer is 5
5 0
3 years ago
About how long does it take for sound to travel 1 Km?
viktelen [127]
It would take roughly 3 seconds.
4 0
3 years ago
Other questions:
  • A transformer consisting of two coils wrapped around an iron core is connected to a generator and a resistor (Resistor is connec
    14·1 answer
  • the net external force on the 24-kg mower is stated to be 51 N. If the force of friction opposing the motion is 24 N, what force
    13·1 answer
  • 15. The
    7·1 answer
  • A bug flies at a velocity of 0.75 m/s into an oncoming breeze blowing at 0.25 m/s. What is the resultant velocity of the bug?
    5·1 answer
  • How does temperature change as you go from the surface toward the center of the earth?
    8·1 answer
  • A constant magnetic field can be used to produce an electric current. True or False?
    8·1 answer
  • What types of alternative fuels did bp pursue after browne became ceo in 1995?
    14·1 answer
  • How do we know what is inside of Earth ?
    9·1 answer
  • In which situation would alley cropping be most useful for sustainable farming?(1 point)
    12·1 answer
  • Why is it advantageous to have two Eyes?​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!