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MrRa [10]
3 years ago
9

1.Is it true to say that, current decreases when passing through a resistor and then increases again upon exiting?

Physics
1 answer:
siniylev [52]3 years ago
8 0
1. Yes, this true as voltage remains constant.
2. Yes, a moving electrical charge generates a magnetic field.
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What condition is required for cloud formation in the atmosphere?
Vedmedyk [2.9K]

Answer: To form a cloud, the air that rises must cool to the point where some of the water vapor molecules "clump together" at a faster pace than they are pulled apart by their thermal energy. These molecules then condense to form the clouds and water droplets.

7 0
4 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
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In a stadium, fans stand up and sit down to produce a wave across the stadium. This type of wave where the material travels perp
puteri [66]
Correct option B

Transverse waves are those waves whose particles vibrate perpendicular to the direction of wave.

Hope This Helps You!
3 0
3 years ago
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Scientists observed a rocky, rotating object orbiting in space. It was 250 km wide. The rocky object was located several times f
mote1985 [20]

The rocky object orbiting in space is most likely referred to as an asteroid.

<h3>What is an Asteroid?</h3>

This is referred to a rocky object which revolve around the sun and are considered too small to be called a planet.

Asteroids was observed with the use of a telescope and is around 250 km wide thereby making it the most appropriate choice.

Read more about Asteroids here brainly.com/question/11996385

4 0
3 years ago
Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!
krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

L = 10 Log\frac{I}{I_0}

20 = 10 Log{I}{10^{-12}}

I_1 = 10^{-10}W/m^2

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

L = 10 Log\frac{I}{I_0}

50 = 10Log\frac{I}{10^{-12}}

I_2 = 10^{-7}W/m^2

now we know that

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}

r_2 = 47 cm

so now the distance from friend must be 47 cm

8 0
3 years ago
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