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AleksandrR [38]
3 years ago
12

A tornado lifts a truck 252 m above the ground ñ. As the storm continues, the tornado throws the truck horizontally. It lands 56

0 m away from where it was picked up. How fast was the truck traveling horizontally through its fight? Round your answer to the nearest tenth.
Physics
2 answers:
sashaice [31]3 years ago
8 0

i think its 200 i hope that helps

Lubov Fominskaja [6]3 years ago
7 0

Answer:

78.1 m/s

Just took it.

Explanation:

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A child on a skateboard experiences a 75 N force with an acceleration of 1.5 m/s2.
cupoosta [38]

Answer:

The mass of the child + skateboard is 50 kg

Explanation:

In this problem, we can apply Newton's second law:

F = ma

where

F is the net force on a system

m is the mass of the system

a is the acceleration of the system

In this problem, our system is the child + the skateboard. The net force on them is

F = 75 N

and their acceleration is

a=1.5 m/s^2

So we can re-arrange the equation above to find their combined mass:

m=\frac{F}{a}=\frac{75}{1.5}=50 kg

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Lady_Fox [76]

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7 0
1 year ago
A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.
kap26 [50]

Answer:

The  frequencies are (f, f_1) =  (6615.4 \ Hz , 19846.2\ Hz)

Explanation:

From the question we are told that

  The  length of the ear canal is  l = 1.3 \ cm  =\frac{1.3}{100}  =  0.013 \ m

   The  speed of sound is assumed to be  v_s  =  344 \ m/s

Now  taking look at a typical  ear canal  we see that we assume it is  a  closed pipe

   Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

            f = \frac{v_s}{4 * l }

 substituting values  

          f = \frac{344}{4 * 0.013 }

         f = 6615.4 \ Hz

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

        f_1 =  \frac{3v_s}{4 * l}

 substituting values  

       f_1 =  \frac{3 *  344}{4 * 0.013}

       f_1 =   19846.2 \ Hz

Given that sound would be loudest in the pipe at the frequency, it implies that the child  will have an increased audible sensitivity at this  frequencies

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Which type of multiplexing is defined by wavelength instead of frequency?​ a. ​wdm b. ​cwdm c. ​dwdm d. ​fdm?
Rina8888 [55]
<span>Multiplexing is the process of combining numerous signal of data or sound on to a single carrier like an optical fiber by using different wavelengths. The type of multiplexing that is defined by wavelength instead of frequency is CWDM which is also known as Coarse Wavelength Division Multiplexing.</span>
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3 years ago
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