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Airida [17]
3 years ago
9

A rugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. He can legally

pass the ball to a teammate as long as the ball's velocity relative to the field does not have a positive x component. Suppose the player runs at speed 3.5 m/s relative to the field while he passes the ball with velocity v with arrowBP relative to himself. If v with arrowBP has magnitude 5.6 m/s, what is the smallest angle it can have for the pass to be legal?

Physics
1 answer:
Over [174]3 years ago
6 0

Answer:

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1  +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ = \frac{v1}{v2}

cosθ = \frac{3.5}{5.6}

θ = 51.31

so minimum angle is 180 - 51.31 = 128.69°

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Explanation:

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2) The vector with the two positive components is a vector in the first quadrant (North and East). That is what North of East 25° means.

3) Regarding the other options:

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</span><span> D) a car moving south of west at an angle of 10°: as in the option C), this is in the third quadrant: the two components are negative.
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3 0
2 years ago
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A force of 70 N is applied to a 28 kg rock causing it to slow down from 25 m/s to 15 m/s, a change in velocity of 10 m/s. How lo
maksim [4K]

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Explanation:

Given

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using the equation of motion

v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s

7 0
3 years ago
You are riding your bike to the mall. You travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an ex
ratelena [41]
I am pretty sure that when you travel the first mile in 10 minutes. The last mile takes you 15 minutes. This is an example of negative acceleration. I consider this to be correct because <span>the second mile was slower. Hope you will agree with me. Regards!</span>
4 0
3 years ago
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a street light is mounted at the top of a 15 foot pole. A man 6 ft tall walks away from the pole wit a speed of 7 ft/s along a s
Mariulka [41]

Answer:

16.3 ft/s

Explanation:

Let d=distance

and

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Therfore,

x=(d + x)

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So,

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x = (2/3)d.

As we know that:

dx=dt

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Also,

Given:

d(d)=dt

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Thus,

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Substitute, d= 7  

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4 0
3 years ago
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Ymorist [56]

Answer:

5.3×10⁴ m/s

Explanation:

From the question,

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make V the subject of the equation

V = M/m.................. Equation 2

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Substitute these values into equation 2

V = 1.6×10⁹/3.0×10⁴

V = 5.3×10⁴ m/s

3 0
3 years ago
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