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mixer [17]
3 years ago
5

Evaluate 2(x+4)^2 - (3y+5)^3 for x= -3 and y= -1

Mathematics
1 answer:
UNO [17]3 years ago
5 0
<span>2(x+4)^2 - (3y+5)^3
at x=-3 and y=-1

2(-3+4)^2 - ((3*-1)+5)^3
2 (1)^2 - (2)^3
2 - 8
(-6)</span>
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Find the exact values of the indicated trigonometric functions. Write fractions in lowest terms.
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For this case we have that by definition of trigonometric relations of a rectangular triangle, that the sine of an angle is given by the opposite leg to the angle on the hypotenuse of the triangle. While the tangent of the same angle is given by the leg opposite the angle on the leg adjacent to the angle.

Then, according to the figure we have:

sin (B) = \frac {7} {25} = 0.28\\tg (B) = \frac {7} {24} = 0.2917

Answer:

sin (B) = \frac {7} {25}\\tg (B) = \frac {7} {24}

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Which expressions are equivalent to this expression?
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Answer:

Option B

Option C

Option D

All of these are correct

Step-by-step explanation:

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Option C is correct because:

x + 3x + 4 = 4x + 4

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Option D is correct because:

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Option A is incorrect because:

4(x + 4) = 4x + 4

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