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My name is Ann [436]
3 years ago
5

How to solve this pythagoras theorem

Mathematics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

The hypotenuse is the longest side thus is (4x + 1)

The legs are 2x and (4x - 1)

Using Pythagoras' theorem, then

(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors

16x² + 8x + 1 = 4x²  + 16x² - 8x + 1 , that is

16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )

- 4x² + 16x = 0 ( multiply through by - 1 )

4x² - 16x = 0 ← factor out 4x from each term

4x(x - 4) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x - 4 = 0 ⇒ x = 4

Now x > 0, thus x = 4

2x = 2(4) = 8

4x - 1 = 4(4) - 1 = 16 - 1 = 15

4x + 1 = 4(4) + 1 = 16 + 1 = 17

Thus

perimeter = 8 + 15 + 17 = 40 cm

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<u>Answer-</u>

\boxed{\boxed{f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0}}

<u>Solution-</u>

Here, n represents the number of months and f(n) represents the number of laptops in the store after n months.

As the store had 150 laptops in the month of January or at the beginning.

So f(0)=150

Every month, 20% of the laptops were sold and 10 new laptops were stocked in the store.

As 20% of laptops were sold, so 80% were in the store.

So, after one month total number of laptops in the store,

\Rightarrow f(1)=0.8(150)+10

\Rightarrow f(1)=0.8(f(0))+10     (\because f(0)=150)

Again after one month total number of laptops in the store,

\Rightarrow f(2)=0.8\times (0.8(150)+10)+10

\Rightarrow f(2)=0.8(f(1))+10     (\because f(1)=0.8(150)+10)

Analyzing the pattern, the recursive function f(n) will be,

f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0


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Answer:

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This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

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Answer:

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Step-by-step explanation:

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1.  c(m) = 33m + f

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hopefully this helps :)

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