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3 years ago

Which of the following does not preserve orientation.

1 answer:

8 0

Translations move the pre-image horizontally or vertically, but retain its orientation.

Reflections reflect across axes, mirroring the pre-image. Reflections result in a change of orientation.

Dilations stretch or shrink the pre-image by a scale factor; they change the pre-image's size but retain the pre-image's orientation.

Rotations rotate around a center point, but don't change the direction of the shape (its orientation).

Answer:
g. reflections

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3 years ago

Read 2 more answers

Evaluate: (d + 1)(d - 1 + 6) <br> d = 2

Allisa [31]

F(d)=(d+1)(d-1+6)
f(d)=(d+1)(d+5)
f(2)=(2+1)(2+5)
f(2)=(3)(7)
f(2)=21

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3 years ago

Directions: Read, analyze, and choose the letter of the correct answer. Write your

svetoff [14.1K]

1) The normal room temperature is said to be about 20°C

2) 5 day is equivalent to 120 hr

3) 756 m³/s is equivalent 56000 L/s

4) It would take the snail 5 hours to crawl 75 m

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

1) The normal room temperature is said to be about 20°C

2) 1 day = 24 hr

5 day = 5 day * 24 hr per day = 120 hr

3) 1 m³ = 1000 L

756 m³/s = 56 m³/s * 1000 L/m³ = 56000 L/s

4) 1 m = 100 cm

75 m = 7500 cm

Time = 7500 / (25 cm/min) = 300 min = 5 hours

Find out more on equation at: brainly.com/question/2972832

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6 0

1 year ago

Nishi invests £2200 at 5% interest per year.

lord [1]

I =(2200×5%×3)/100
=3.3
3 years = 3.3 +2200
= 2203.30
I =(2200×5%×5)/100
=5.50
5 years =5.50 +2200
= 2205.50

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3 years ago

Read the problem to choose the correct method, then solve. A farmer buys a tractor for $50,000. If the tractor depreciates 10% p

OlgaM077 [116]

Answer:

The correct option is, Exponential Decay, $23,914.85.

Step-by-step explanation:

A farmer buys a tractor for $50,000.

It is provided that the the tractor depreciates 10% per year.

The exponential function for decay is:

$y=a\cdot (1-r\%)^{t}$

Here,

a = initial value

r = decay rate

t = time

Compute the value of the tractor in 7 years as follows:

$y=a\cdot (1-r\%)^{t}$

$=50000\times (1-0.10)^{7}\\\\=50000\times 0.4782969\\\\=23914.845\\\\\approx 23914.85$

Thus, the correct option is, Exponential Decay, $23,914.85.

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2 years ago