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Mademuasel [1]
2 years ago
13

Solve the system of linear equations by elimination. x + 5y = 15 and -x - 2y = 0

Mathematics
1 answer:
Zolol [24]2 years ago
4 0

Answer:

X= - 10

Y=5

Step-by-step explanation:

First add the equations and x will be eliminated, then solve for y as a normal linear function, and the answer is 5.

Substitute thw y in any function, I substituted in the first one, and solved for x and got negative 10 as an answer.

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GREYUIT [131]
3.5 is your answer. :)



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The recursive function for a sequence is given below.
masya89 [10]

Answer:

f(5) = 3200

Step-by-step explanation:

Using the recursive formula to generate the terms, that is

f(2) = 2 × f(1) = 2 × 200 = 400

f(3) = 2 × f(2) = 2 × 400 = 800

f(4) = 2 × f(3) = 2 × 800 = 1600

f(5) = 2 × f(4) = 2 × 1600 = 3200

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3 years ago
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Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
stiv31 [10]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• <u>Radius</u> = 5 units

• <u>Centre </u> = (0,0)

<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

  • Here we can see that the distance of point from centre is less than the radius.

<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>

5 0
3 years ago
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5^(-7)*5^(12)*5^(-2)<br><br> with steps
docker41 [41]

Answer:

=125

Step-by-step explanation:

5−7)(512)(5−2)

=

1

78125

(512)(5−2)

=

1

78125

(512)(5−2)

=(

1

78125

(244140625))(5−2)

=3125(5−2)

=3125(

1

25

)

=125

3 0
3 years ago
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Solve the system of equations algebraically. Verify your
xz_007 [3.2K]

Answer:

The solution is the point (0.5,-3)

Step-by-step explanation:

we have

y=4x-5 ----> equation A

y=-3 ----> equation B

Solve the system by substitution

Substitute equation B in equation A

-3=4x-5

Solve for x

Adds 5 both sides

-3+5=4x

2=4x

Divide by 4 both sides

x=0.5

therefore

The solution is the point (0.5,-3)

<em>Verify your  answer using the graph</em>

using a graphing tool

Remember that the solution of the system of equations is the intersection point both graphs

The intersection point is (0.5,-3)

therefore

The solution is the point (0.5,-3)

see the attached figure

8 0
3 years ago
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