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Maksim231197 [3]
3 years ago
13

An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up wit

h a velocity of +14.2 m/s and measures a time of 15.9 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (positive = up, negative = down).
Physics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

a= -1.8m/s²

Explanation:

The equation for position x for a constant acceleration a, time t, initial velocity v₀ and initial position x₀ is given by:

x=\frac{1}{2}at^2+v_0t+x_0

For the case that x = x₀, the equation becomes:

0=\frac{1}{2}at^2 +v_0t

Solving for a:

a=-\frac{2v_0}{t}

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Darya [45]
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6 0
3 years ago
4. An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5
Mazyrski [523]

Answer:

11.87 ms⁻¹

Explanation:

You can use the kinematic equation

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Rina8888 [55]

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A 24.0N picture hangs from a nail in the wall. The diameter of the nail is 2.00 mm. The shear stress on the nail is
san4es73 [151]
Weight tending to shear the pin is
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τ = (24.0 N)/(3.1416 x 10⁻⁶ m²)
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Answer: 7.64 Mpa
8 0
4 years ago
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vodomira [7]

Answer:

Gravitational attraction of the sun.

Explanation:

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3 years ago
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