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2 years ago

10

The work-energy theorem states that a force acting on a particle as it moves over a changes the energy of the part

icle if the force has a component parallel to the motion.
Choose the best answer to fill in the blanks above:

A. distance/potential
B. distance/kinetic
C. vertical displacement/potential
D. none of the above

1 answer:

svetoff [14.1K]2 years ago

5 0

Answer:

B. distance/potential

Explanation:

Quizlet

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Consider a river flowing toward a lake at an average velocity of 3 m/s. the river height is 90m above the lake. what is the tota

strojnjashka [21]

Kinetic energy per unit of mass is

$K=\frac{v^{2} }{2}$

Given, $v=3m/s^{2}$

Therefore,

$K=\frac{(3^{2} m/s^{2} )^2}{2}$

$K=4.5 J/kg$

Now potential energy per unit mass is

$p=g\times h$

Given, $h=90 m$

Therefore,

$p= 9.8m/s^2 \times 90$

$p=882.9 J/kg$

Thus, total mechanical energy of the river water per unit mass is

$T=K+p=(4.5+882.9)J/kg$

$T=887.9 J/kg$

OR

$T=0.887 kJ/kg$

6 0

2 years ago

What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?

Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

$I=\dfrac{E^2}{2\mu_{0}c}$

$E=\sqrt{2\times I\mu_{0}c}$

Put the value into the formula

$E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}$

$E=931.17\ N/C$

Using formula of magnetic field

$B = \dfrac{E}{c}$

Put the value into the formula

$B=\dfrac{931.17}{3\times10^{8}}$

$B=0.0000031039\ T$

$B=3.10\times10^{-6}\ T$

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

$F=\dfrac{Gm_{s}M_{e}}{r^2}$

Put the value into the formula

$F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}$

$F=3.522\times10^{22}\ N$

We need to calculate the radiation force

Using formula of force

$F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}$

Put the value into the formula

$F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2$

$F_{R}=4.8\times10^{8}\ N$

The gravitational and solar electromagnetic pressure forces of the sun on the earth

$\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}$

$\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}$

Hence, This is the required solution.

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3 years ago

The force of attraction that the Earth exerts on all objects is called _____. mass weight gravity inertia

Annette [7]

Gravity. Hope this helped! Good luck :)

8 0

3 years ago

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A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1250 pou

Ierofanga [76]

Answer:

Option d is correct.

The magnitude of the resultant force upon the piling = 2930 lbs.

Explanation:

Resultant of a group of forces = vector sum of the forces.

Force 1 = (-1250î) lbs

Force 2 = (2650j) lbs

Resultant = (-1250î + 2650j) lbs

The magnitude of the resultant = √[(-1250)² + (2650)²] = 2930 lbs.

Or in visualization method, the two forces presented form a right angled triangle with the resultant of the two forces.

Hence, using Pythagoras theorem,

F₁² + F₂² = R²

(1250)² + (2650)² = R²

R = √[(1250)² + (2650)²] = 2930 lbs.

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3 years ago

In the modern quantum–based atomic theory, what is the name given to a particular space around the nucleus in which an electron

Marina86 [1]

<span>The correct answer is: Atomic orbital

Explanation:
In the modern quantum-based atomic theory, an atomic orbital is a mathematical function that is used to explain the wave-like behavior of an electron in an atom. In other words, the space around the nucleus in which an electron moves is expressed by the atomic orbital. Hence, the correct answer is Atomic orbital.</span>

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3 years ago

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