The solution would be like
this for this specific problem:
V^2 = 2AS = 2FS/M
V = sqrt(2FS/M) =
sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps
So the speed of the arrow as it leaves the bow
is 42.5 mps.
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
Answer:
Explanation:
Hi!
In order to obtain the Lagrangian of the system we must first write the Kinetic and Potential Energies. Lets orient our axes such that the axis of the cone coincide with the z axis. In cilindrical coordinates we have
- (1)
But, since the particle is constrained to move on the surface of the cilinder, we have the following relation between r and z:

or:
- (2)
and:
replacing (2) in (1) we obtain:
- (3)
Now the kinetic energy is given as:
- (4)
And the potential energy is given by:

So the Langrangian is given by:

And the equations of motion are:
For θ

For r

Obtained from the Euler-Langrange equations
Here the conserved quantity is given by the first equation of motion, namely:

Which is the magnitude of the angular momentum
Answer:
Obviously Our Yellow Star: The Sun....
Explanation:
With a staggering mass of 1.989 × 10^30 kg as well as a gravitation pull of about 274 ms^-1. I think, no other object in our solar system at least have those properties. Not to mention Sun makes <em>99.86% of our solar system </em>combined.
Explanation:
P =F * v
F = m * a = 65 kg * 9.81 ms^-2 * 12 passengers
v = d/t = 150m / 64 s
I think you can calculate and substitute this units should be watts