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jeyben [28]
3 years ago
10

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

icle if the force has a component parallel to the motion.
Choose the best answer to fill in the blanks above:

A. distance/potential
B. distance/kinetic
C. vertical displacement/potential
D. none of the above
Physics
1 answer:
svetoff [14.1K]3 years ago
5 0

Answer:

B. distance/potential

Explanation:

Quizlet

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A 87 arrow is fired from a bow whose string exerts an average force of 105 on the arrow over a distance of 75 .
timofeeve [1]

The solution would be like this for this specific problem:

 

V^2 = 2AS = 2FS/M

V = sqrt(2FS/M) = sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps

So the speed of the arrow as it leaves the bow is 42.5 mps.

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
3 years ago
Lagrangian mechanics. Determine the equations of motion for a particle of mass m constrained to move on the surface of a cone in
maria [59]

Answer:

Explanation:

Hi!

In order to obtain the Lagrangian of the system we must first write the Kinetic and Potential Energies. Lets orient our axes such that the axis of the cone coincide with the z axis. In cilindrical coordinates we have

v^{2} = \frac{dr}{dt}^{2}  +r^{2} \frac{d\theta }{dt} ^{2} +\frac{dz}{dt} ^{2} - (1)

But, since the particle is constrained to move on the surface of the cilinder, we have the following relation between r and z:

\frac{r}{z}=tan(45)

or:

z = r cot(45) - (2)

and:

\frac{dz}{dt} = \frac{dr}{dt} cot(45)

replacing (2) in (1) we obtain:

v^{2} = \frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2}  - (3)

Now the kinetic energy is given as:

T = \frac{1}{2}m(\frac{dr}{dt}^{2} (1+cot(45))+r^{2}\frac{d\theta }{dt} ^{2}) - (4)

And the potential energy is given by:

V = -mgz = -mgr cot(45)

So the Langrangian is given by:

L = T - V= \frac{1}{2}m(\frac{dr}{dt}^{2}(1+cot(45)+r^{2})\frac{d\theta }{dt} ^{2}) + mgr cot(45)

And the equations of motion are:

For θ

\frac{d}{dt} (mr\frac{d\theta}{dt}) = 0-->mr{d\theta}{dt}=c

For r

\frac{d}{dt}(m\frac{dr}{dt}(1+cot(45) )= mgcot(45)+mr\frac{d\theta}{dt} ^{2}\\m\frac{d^{2} r}{dt^{2} }(1+cot(45)= mgcot(45)+mr\frac{d\theta}{dt} ^{2}

Obtained from the Euler-Langrange equations

Here the conserved quantity is given by the first equation of motion, namely:

mr\frac{d\theta}{dt}=c

Which is the magnitude of the angular momentum

7 0
3 years ago
"In the far future, a visiting tourist from another planetary system asks to see the most massive object in our solar system. Wh
Andrei [34K]

Answer:

Obviously Our Yellow Star: The Sun....

Explanation:

With a staggering mass of 1.989 × 10^30 kg as well as a gravitation pull of about 274 ms^-1. I think, no other object in our solar system at least have those properties. Not to mention Sun makes <em>99.86% of our solar system </em>combined.

7 0
3 years ago
1.A student pushes a 20.0 kg mass 10.0 m across a floor with a horizontal force of 80.0 N. Calculate the amount of work that the
Alina [70]
W = (10.0 m)(80.0 N)
W = 800 J
7 0
3 years ago
(b) A lift (elevator) in a high building transports 12 passengers, each of mass 65 kg, through a
PSYCHO15rus [73]

Explanation:

P =F * v

F = m * a = 65 kg * 9.81 ms^-2 * 12 passengers

v = d/t = 150m / 64 s

I think you can calculate and substitute this units should be watts

5 0
3 years ago
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