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nadya68 [22]
4 years ago
11

A sample of gas has a pressure of 3.00 atm at 25 degrees Celsius. What would the pressure be at 52 degrees Celsius if the volume

stays constant? Which gas law does this problem represent?
Chemistry
1 answer:
Doss [256]4 years ago
8 0
The law that relate pressure and temperature of gases at constant volumes is Gay-Lussac's Law.

It states that the pressure of a fixed mass of gas is directly proportional to the absolute temperature when the volume is constant.

 P / T = constant => P1 / T1 = P2 / T2

=> P2 = T2 * P1 / T1

Remember that the formula uses absolute temperatures.

T2 = 52 + 273.15 = 325.15 K

T1 = 25 + 273.15 = 298.15 K

=> P2 = 325.15K * 3.00 atm / 298.15K = 3.27 atm.

Answer: 3.27 atm
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Answer:

1.55×10²² molecules.

Explanation:

We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

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