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tatuchka [14]
4 years ago
5

What is the density of a block of gold that occupies 1000 ml and has a mass of 3.5 kg? Show your work

Chemistry
1 answer:
tiny-mole [99]4 years ago
5 0

Answer:

Density of block of gold is <em>3.5 g/cm³.</em>

Explanation:

Given data:

Volume of block = 1000 mL

Mass of block = 3.5 kg (3.5×1000 = 3500 g)

Density of block = ?

Solution:

Density of substance is calculated by dividing the mass of substance over its volume.

Formula:

d = m/v

d = 3500 g/ 1000 mL

d = 3.5 g/mL

or

d = 3.5 g/cm³             (1ml = 1cm³)

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  • 4.6 x $ \sf{10^{22}}$ atoms of an element weigh 13.8g.

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The atoms of $ \sf{ 6.02 \times 10^{13}}$ will weigh;

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Angelina_Jolie [31]

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<h3>What exactly are polar and nonpolar bonds?</h3>

Polar covalent bonds develop when the distribution of electrons among atoms is uneven, whereas nonpolar side chains develop when the distribution of electrons is more even. The reason for the unequal sharing of electrons is because the atoms receiving them have various electronegativities.

<h3>How are polar bonds created?</h3>

Whenever a single pair of electrons is not shared equally, a polar molecule bond is created. This is caused by the electronegativity difference between the two elements. An unit of h as well as an unit of bromine share a pair of electrons, but not evenly.

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3 0
3 years ago
A certain isotope has 53 protons 78 neutrons and 53 electrons. What is its atomic number? What is the mass number of this atom?
statuscvo [17]

Answer:

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atomic no. = no. of protons

= 53 proton

mass = no. of protons + no. of

neutrons

= 53 + 78

= 131

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3 years ago
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