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tatuchka [14]
3 years ago
5

What is the density of a block of gold that occupies 1000 ml and has a mass of 3.5 kg? Show your work

Chemistry
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

Density of block of gold is <em>3.5 g/cm³.</em>

Explanation:

Given data:

Volume of block = 1000 mL

Mass of block = 3.5 kg (3.5×1000 = 3500 g)

Density of block = ?

Solution:

Density of substance is calculated by dividing the mass of substance over its volume.

Formula:

d = m/v

d = 3500 g/ 1000 mL

d = 3.5 g/mL

or

d = 3.5 g/cm³             (1ml = 1cm³)

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Imagine you have 50,000 atoms of uranium-238. If U-238 has a half-life of 4.5 billion years, how many U-238 atoms will be left a
Lelechka [254]

Answer:25,000

Explanation:

I took the test

8 0
2 years ago
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a sample of the hydrate of sodium carbonate has a mass of 8.85 g. it loses 1.28 g when heated. find the molar ratio of this comp
xenn [34]

Answer:

Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.

Explanation:

From the given,

Mass of sodium carbonate Na_{2}CO_{3}.XH_{2}O = 8.85 g

Loss mass H_{2}O = 1.28 g

Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g

7.57 g Na_{2}CO_{3} \times \frac{1mol}{106 g} =\frac{0.0714}{0.0714}=1

1.28g H_{2}O \times \frac{1mol}{18 g} =\frac{0.0711}{0.0714}=1

Therefore, the compound has only one water molecule.

Molecular formula of the compound is Na_{2}CO_{3}.H_{2}O an name of the compound is <u>sodium carbonate mono hydrate.</u>

Hence, the type of the compound is Mono hydrate.

8 0
3 years ago
How many moles of oxygen are necessary to completely react with propane (C3H8) to produce 16.3 mol of water according to the fol
velikii [3]
The balanced chemical reaction is expressed as:

<span>C3H8 + 5 O2 -> 3 CO2 + 4 H2O

We are given the amount of water produced. We use this amount for the calculations. We do as follows:

16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed

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4 0
3 years ago
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A chemist prepares a solution of copper(l) sulfate (CuSo4) by measuring out 11.7 g of copper(II) sulfate into a 350. mL volumetr
Ksju [112]

Answer:

0.209 mol/L

Explanation:

Given data

  • Mass of copper(lI) sulfate (solute): 11.7 g
  • Volume of solution: 350 mL = 0.350 L

The molar mass of copper(Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:

11.7 g × (1 mol/159.61 g) = 0.0733 mol

The molarity of copper(Il) sulfate is:

M = moles of solute / liters of solution

M = 0.0733 mol / 0.350 L

M = 0.209 mol/L

6 0
3 years ago
A student drew a diagram of the quantum model of an atom, as shown. A small circle is shown. Six light gray spheres and six dark
Rufina [12.5K]

Answer:

The diagram is incorrect because there is only a single type of particle at the center of the atom.

Explanation:

The small circle at the centre of the sphere which contains six light gray spheres and six dark gray spheres represents the nucleus of the atom which is found at the centre of the atom.

The nucleus contains only one type of particle which is the proton. Hence the representation of two particles at the centre of the circle makes the model incorrect.

8 0
3 years ago
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