Answer:
Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.
Explanation:
From the given,
Mass of sodium carbonate 
= 8.85 g
Loss mass 
= 1.28 g
Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g
Therefore, the compound has only one water molecule.
Molecular formula of the compound is 
an name of the compound is <u>sodium carbonate mono hydrate.</u>
Hence, the type of the compound is Mono hydrate.
The balanced chemical reaction is expressed as:
<span>C3H8 + 5 O2 -> 3 CO2 + 4 H2O
We are given the amount of water produced. We use this amount for the calculations. We do as follows:
16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed
Hope this answers the question. Have a nice day.</span>
Answer:
0.209 mol/L
Explanation:
Given data
- Mass of copper(lI) sulfate (solute): 11.7 g
- Volume of solution: 350 mL = 0.350 L
The molar mass of copper(Il) sulfate is 159.61 g/mol. The moles corresponding to 11.7 grams are:
11.7 g × (1 mol/159.61 g) = 0.0733 mol
The molarity of copper(Il) sulfate is:
M = moles of solute / liters of solution
M = 0.0733 mol / 0.350 L
M = 0.209 mol/L
Answer:
The diagram is incorrect because there is only a single type of particle at the center of the atom.
Explanation:
The small circle at the centre of the sphere which contains six light gray spheres and six dark gray spheres represents the nucleus of the atom which is found at the centre of the atom.
The nucleus contains only one type of particle which is the proton. Hence the representation of two particles at the centre of the circle makes the model incorrect.
