Answer:
54.1°C
Explanation:
Now we have the following parameters from the question;
Heat applied (H)= 18.0×10^3 Joules
Mass of the water(m)= 250g= 0.25Kg
Initial temperature of the water (θ1)= 37°C
Final temperature of the water (θ2)= the unknown
Heat capacity of water (c) = 4200JKg-1
From ;
H= mc(θ2-θ1)
Substituting values appropriately
18×10^3= 0.25 × 4200(θ2-37)
18×10^3 = 0.25 × (4200θ2 - 155400)
18×10^3 = 1050θ2 - 38850
18×10^3 + 38850 = 1050θ2
56850 = 1050θ2
θ2= 56850/1050
θ2= 54.1°C
Spontaneous is no spontaneous
Analytical chemistry -- A task that would fall into this area of chemistry is measuring the level of lead in drinking water.
Ammonia isn't an element, it's a compound made by mixing the elements Nitrogen and Hydrogen in the Haber process. Therefore, it isn't on the periodic table
0.05M is the concentration of the solution.
The amount of a chemical substance in a mixture is expressed by the substance's concentration. Concentration can be expressed in numerous ways. In chemistry, the terms "solvent" and "solute" are used to denote the substance of interest and the medium in which it is dissolved, respectively
Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V. To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.
C = m / V
C = 10 / 200
C = 0.05M.
Learn more about concentration here:
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