Answer:
0.58 atm
Explanation:
Step 1: Given data
- Total pressure of the gaseous mixture (P): 1.05 atm
- Partial pressure of N₂ (pN₂): 0.35 atm
- Partial pressure of H₂ (pH₂): 0.12 atm
- Partial pressure of CO₂ (pCO₂): ?
Step 2: Calculate the partial pressure of CO₂
The total pressure of the gaseous mixture is equal to the sum of the partial pressures of the individual gases.
P = pN₂ + pO₂ + pCO₂
pCO₂ = P - pN₂ - pO₂
pCO₂ = 1.05 atm - 0.35 atm - 0.12 atm = 0.58 atm
Answer:
53.85%
Explanation:
Data obtained from the question include:
Mass of antimony (Sb) = 27.6g
Mass of Fluorine (F) = 32.2g
Mass of compound = 59.8g
Percentage composition of fluorine (F) =..?
The percentage composition of fluorine can be obtained as follow:
Percentage composition of fluorine = mass of fluorine/mass of compound x 100
Percentage composition of fluorine = 32.2/59.8 x 100
= 53.85%
Therefore, the percentage composition of fluorine in the compound is 53.85%
P1V1/T1=P2V2/T2 P2=1/2 P1 V1=1 T1=298K
1 P1/298= (1/2) P1V2/373 cross P1
1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L
Answer:
<h2>2000 N</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 500 × 4
We have the final answer as
<h3>2000 N</h3>
Hope this helps you
Most likely the transition metals