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Firdavs [7]
3 years ago
6

PLEASE HELP!?Consumers must eat other organisms for energy. Which organisms are consumers in this food chain?

Chemistry
1 answer:
Vitek1552 [10]3 years ago
4 0

Answer:

Consumers must consume other organisms to get the food that they need and are known as Heterotrophs as they cannot make their own glucose. These consumers eat producers (plants). Herbivores are considered as first order consumers. These consumers eat consumers and producers (animals and plants).

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What's the partial pressure of carbon dioxide in a container that holds .35 atm of nitrogen, and .12 atm of hydrogen and has a t
ivanzaharov [21]

Answer:

0.58 atm

Explanation:

Step 1: Given data

  • Total pressure of the gaseous mixture (P): 1.05 atm
  • Partial pressure of N₂ (pN₂): 0.35 atm
  • Partial pressure of H₂ (pH₂): 0.12 atm
  • Partial pressure of CO₂ (pCO₂): ?

Step 2: Calculate the partial pressure of CO₂

The total pressure of the gaseous mixture is equal to the sum of the partial pressures of the individual gases.

P = pN₂ + pO₂ + pCO₂

pCO₂ = P - pN₂ - pO₂

pCO₂ = 1.05 atm - 0.35 atm - 0.12 atm = 0.58 atm

5 0
3 years ago
A sample of a pure compound that weighs 59.8 g contains 27.6 g Sb (antimony) and 32.2 g F (fluorine). What is the percent compos
Rama09 [41]

Answer:

53.85%

Explanation:

Data obtained from the question include:

Mass of antimony (Sb) = 27.6g

Mass of Fluorine (F) = 32.2g

Mass of compound = 59.8g

Percentage composition of fluorine (F) =..?

The percentage composition of fluorine can be obtained as follow:

Percentage composition of fluorine = mass of fluorine/mass of compound x 100

Percentage composition of fluorine = 32.2/59.8 x 100

= 53.85%

Therefore, the percentage composition of fluorine in the compound is 53.85%

3 0
3 years ago
You have a balloon containing 1 L of air at STP in a vacuum chamber. What will the volume of the balloon be when you reduce the
Ipatiy [6.2K]
P1V1/T1=P2V2/T2   P2=1/2 P1 V1=1 T1=298K

1 P1/298= (1/2) P1V2/373  cross P1

1/298=1/2V2/373
1/298=1/V2 746
v2=746/298
V2=2.5L


5 0
4 years ago
It took 500N of force to push a car 4 meters. how much work is done?
Agata [3.3K]

Answer:

<h2>2000 N</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 500 × 4

We have the final answer as

<h3>2000 N</h3>

Hope this helps you

7 0
3 years ago
The semi-conductors on the periodic table are classified as
Mila [183]
Most likely the transition metals
4 0
3 years ago
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