Answer:
A
Explanation:
It is so because the low air pressure create vacuum and the air from high pressure area move toward the low air pressure.
Answer:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK
Explanation:
The temperature of an object can be written using different temperature scales.
The two most important scales are:
- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).
- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.
The expression to convert from Celsius degrees to Kelvin is:
Therefore in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK
Answer:
They are a base and an acid, so they neutralize each other.
Explanation:
Sodium hydroxide is a strong base. Hydrochloric acid is a strong acid.
They react with (neutralize) each other to form a salt (sodium chloride) and water.
NaOH + HCl ⟶ NaCl + H₂O
Answer:
c. F1-
Explanation:
In this chemical reaction the expression is:
HF + NaF → NaHF2
The ion that always keep the negative charge is the fluorine with a -1, if in this mixture there is more positive ions (H1+) the negative ion (F1-) will join with them.
Remember that also the Cl1- will be free, but the fluorine is more reactive than the fluorine.
Answer:
The rate of change of the temperature is 0.0365 Kelvin per minute.
Explanation:
<u>Step 1</u>: Given data
ideal gas law: P*V = n*R*T
with P= pressure of the gas ( in atm) = 9.0 atm
with V= volume of the gass (in L) =12L
with n = number of moles = 10 moles
R = gas constant = 0.0821 L*atm* K^−1*mo^−1
T = temperature = TO BE DETERMINED
The volume decreases with a rate of 0.17L/min = dV/dT = -0.17
The pressure increases at a rate of 0.13atm/min = dP/dT
<u>Step 2:</u> The ideal gas law
P * [dV/dT] + V * [dP/dT] = nR * dT/dt
9 atm * (-0.17L/min) + 12L * 0.13atm/min = 10 moles * 0.0821 L*atm* K^−1*mo^−1 *dT/dt
0.03 = 0.821 * dT/dt
dT/dt = 0.03/0.821
dT/dt = 0.0365
Since the gas constant is expressed in Kelvin and not in °C, this means that <u>the rate of chagnge of the temperature is 0.0365 Kelvin per 1 minute.</u>
