All categories

2 years ago

Find the 11th term of the geometric sequence 6, -18, 54,

Mathematics

1 answer:

horsena [70]2 years ago

8 0

Answer:

354294

Step-by-step explanation:

a₁ = 6 = 6 * (-3)⁰

a₂ = -18 = 6 * (-3)¹

a₃ = 54 = -18 * (-3) = 6 * (-3)²

a₁₁ = 6 * (-3)¹⁰ = 354294

You might be interested in

What is m∠M ? Brainliest to correct answer <3

nika2105 [10]

Sum of interior angles of triangle = 180

x + x + 6 + 3x - 16 = 180

5x - 10 = 180

5x = 190

x = 38

<M = 3(38) - 16

<M = 114 - 16

<M = 98°

5 0

2 years ago

Someone know how to do this Im very confusing about how to do it

Sidana [21]

It would be e, because it went down 10 instead of 5

3 0

2 years ago

Find the angles between -pi and pi that satisfy:<br><br> (−√3) sin(v)+cos(v)=√3

MAXImum [283]

Observe that

$\sin\left(\dfrac\pi6-v\right)=\sin\dfrac\pi6\cos v-\cos\dfrac\pi6\sin v=\dfrac12\cos v-\dfrac{\sqrt3}2\sin v$

In the original equation, divide both sides by $\dfrac12$ :

$-\sqrt3\sin v+\cos v=\sqrt3\implies\dfrac12\cos v-\dfrac{\sqrt3}2\sin v=\dfrac{\sqrt3}2$

$\implies\sin\left(\dfrac\pi6-v\right)=\dfrac{\sqrt3}2$

Next,

$\sin x=\dfrac{\sqrt3}2\implies x=\dfrac\pi3+2n\pi,x=\dfrac{2\pi}3+2n\pi$

where $n$ is any integer. Then

$\sin\left(\dfrac\pi6-v\right)\implies v=-\dfrac\pi6-2n\pi,v=-\dfrac\pi2-2n\pi$

Fix $n=0$ to ensure $-\pi$ , so that

$v=-\dfrac\pi6,v=-\dfrac\pi2$

3 0

3 years ago

Simplify 6x+(- 9)-9(5x+5)+x

Hatshy [7]

Answer:

Step-by-step explanation:

I've already answered this question.

4 0

3 years ago

Read 2 more answers

For what values of k does the graph of y=-2x^2+5x+k not cut the x axis

goldenfox [79]

The answer is 4 because there r three 3 2s

6 0

2 years ago