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2 years ago

A solution that contains many dissolved molecules in a fixed amount of solution is called

Chemistry

1 answer:

vfiekz [6]2 years ago

3 0

Answer:

A solution that contains many dissolved molecules in a fixed amount of solution is called concentrated (first choice)

Explanation:

Concentration is the term used to express the amount of solute in a solution. The concentration is a measure of how much solute is dissolved.

The term concentrated is a qualitative form to describe that a solution has a high concentration; this is, it contains many dissolved molecules in certain volume of solution).

The opposite to concentrated is diluted (choice 3). This is, a diluted solution contains a small amount of solute (molecules dissolved) in a fixed amount of solution.

The other two choices (2 and 4) use the terms strong and weak. Those terms refere to a special kind of solutions, acids and bases, and designate how much they ionize (dissociate) in the solution: a strong acid or base dissociates in a high percent, while a weak acid or base dissociates poorly.

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The density of silver is 10.5 g/cm3. What is the mass (in kilograms) of a cube of silver that measures 0.94 m on each side?

Rzqust [24]

Answer:

8721.132 Kg.

Explanation:

The following data were obtained from the question:

Density (D) of silver = 10.5 g/cm³

Length (L) of silver = 0.94 m

Mass (m) of silver =.?

Next, we shall determine the volume of silver. This can be obtained as follow:

Volume = Length × Length × Length

Volume = L × L × L

Volume = L³

Length (L) of silver = 0.94 m

Volume (V) of silver =?

Volume (V) of silver = 0.94³

Volume (V) of silver = 0.830584 m³

Next, we shall convert 0.830584 m³ to cm³. This can be obtained as follow:

1 m³ = 1×10⁶ cm³

Therefore,

0.830584 m³ = 0.830584 m³ / 1 m³ × 1×10⁶ cm³

0.830584 m³ = 830584 cm³

Therefore, 0.830584 m³ is equivalent 830584 cm³.

Thus, the volume of the silver is 830584 cm³.

Next, we shall determine the mass of the silver. This can be obtained as follow:

Density (D) of silver = 10.5 g/cm³

Volume of the silver = 830584 cm³.

Mass of silver =.?

Density = mass /

10.5 = mass of silver /830584

Cross multiply

Mass of silver = 10.5 × 830584

Mass of silver = 8721132 g

Finally, we shall convert the mass of silver, 8721132 g to kilogram (kg). This can be obtained as follow:

1000 g = 1 Kg

Therefore,

8721132 g = 8721132 g / 1000 g × 1 Kg

8721132 g = 8721.132 Kg

Therefore, the mass of each cube of silver is 8721.132 Kg

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3 years ago

At a certain temperature Kc = 9.0 for the equilibrium 24() ⇔ 22(). What is

Iteru [2.4K]

Answer:

Explanation:

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3 years ago

As the organsims develops, its cells become -------

exis [7]

It's cells become larger in numbers.

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3 years ago

How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?

Katen [24]

The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J

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3 years ago

Read 2 more answers

1. The solubility of AgNO3 at 20°C is 222.0g AgNO3/100g H2O. What mass of AgNO3 can be dissolved in 250 g of water at 20°C? Reca

neonofarm [45]

Answer :

(1) The mass of silver nitrate is, 555 g

(2) The solubility of the gas will be, 0.433 g/L

Solution for Part 1 :

From the given data we conclude that

In 100 gram of water, the amount of silver nitrate = 222 g

In 250 gram of water, the amount of silver nitrate = $\frac{222}{100}\times 250=555g$

Therefore, the mass of silver nitrate is, 555 g

Solution for Part 2 :

Formula used : $S_1P_1=S_2P_2$ (at constant temperature)

where,

$S_1$ = initial solubility of methane gas = 0.026 g/L

$S_2$ = final solubility of methane gas

$P_1$ = initial pressure of methane gas = 1 atm

$P_2$ = final pressure of methane gas = 0.06 atm

Now put all the given values in the above formula, we get the solubility of methane gas.

$(0.026g/L)\times (1atm)=S_2\times (0.06atm)$

$S_2=0.433g/L$

Therefore, the solubility of the gas will be, 0.433 g/L

5 0

3 years ago