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olya-2409 [2.1K]
3 years ago
12

If an atom of the following element had a neutral charge, how many electrons would it have?

Chemistry
1 answer:
Yakvenalex [24]3 years ago
8 0

Answer:

31

Explanation:

In order for an atom to have a neutral charge, it needs to have the same number of protons and electrons. You can see by the illustration that the atomic number is 31, so this element has 31 protons. Knowing that, we also know that it must have 31 electrons to be neutral.

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Calculate the volume of the acid solution and the volume of the conjugate base solution that would be needed to prepare a buffer
bogdanovich [222]

Answer:

Explanation:

This can be contradictory, depending on whether the 0.1 M

is the total species concentration or the concentration of each of the two components. I'll consider this to be the former...

VA− = 9.125 mL

VHA = 15.875 mL

The Henderson-Hasselbalch equation is:

pH = pKa + log [A−][HA]

We have a pH 4.5

solution of acetic acid and acetate, so from there we can get the ratio of weak acid to conjugate base:

[A−][HA]=10

pH − pKa = 104.5 − 4.74 = 0.5754

Now, if the total concentration is

0.10 M , then:

[HA] + [A−] 0.5754

[HA] = 0.10 M

⇒[HA] = 0.10 M 1.0000 +0.5754

= 0.0635 M

−−−−−−−−

⇒[A−] = 0.0365 M

−−−−−−−−

and these concentrations are AFTER mixing. Since the total volume is 50 mL , or 0.050 L, the mols of each component (which are constant!) are:

nA − = 0.0365 molL × 0.050L =

0.001825 mols

−−−−−−−−−−−−

nHA = 0.0635 molL × 0.050L =

0.003175 mols

−−−−−−−−−−−−

So, if both of the starting concentrations were

0.20 M, we can find the volume they each start with:

VA − = 1 L0.20mols

A− × 0.001825mols A− = 0.009125 L = 9.125 mL

−−−−−−−−

VHA = 1 L 0.20 mols HA × 0.003175

mols HA = 0.015875 L = 15.875 mL

−−−−−−−−−

And this should make sense, because the total starting volume is

25.000 mL , the total ending volume is twice as large; the total species concentration is half the concentration that both species started with.

6 0
3 years ago
Which element melts at room temperature?
just olya [345]
Francium is an element that melts at room temperature. Francium is a highly reactive element, and only contains one valence electron, which is very ironic in my opinion. 
4 0
3 years ago
Read 2 more answers
Which principal energy level of an atom contains an electron with the lowest energy?
Ad libitum [116K]
The answer is a.n=1 because it makes sence
4 0
4 years ago
Read 2 more answers
How can we find the number of moles in equilibrium?
pychu [463]
<span>You can find the number of moles in equilibrium if you got the chemical reaction correctly. Make sure that you got the exact chemical formula of the substance that is reacting and the yielded product. If you got them, balance the chemical reaction. If the chemical reaction is balanced, the system is in equilibrium. You can find the number of moles in equilibrium at the coefficients of the chemical substances you are balancing. For example, N2 + 3H2 -> 2NH3. The number of moles of N2 is 1, H2 is 3 and NH3 is 2.</span>
5 0
3 years ago
WILL GIVE BRAINLIEST <br> Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.
Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

<u>Structure of H2S :</u>

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) <u>3s(2 )3p(4)</u>

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these  6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4  are non- bonding  and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

<u>Structure of H2S :</u>

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron  are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : <u><em>According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.</em></u>

<u><em>Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S  shifts way from lone pair</em></u>

5 0
3 years ago
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