C bc i am a professor at Yale and it is simplistic............................................................... <span />
+ + + + + +
4 is positive or + and so is 2
hope it helps
<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
18. The perimeter is simply √3 + √3 + √3 + √3 or 4√3cm, since the perimeter is just all sides added together. You could add the decimal numbers together using a calculator, which I'm not sure if you're supposed to do in your class.
The area is just width times length, so √3 • √3 = 3cm².
19. The perimeter is 2√5 + 2(9 - √5).
This can also be written as 2√5 + 18 - 2√5, which leaves you with a perimeter of 18ft.
The area would be √5 • (9 - √5), which leaves you with (9√5 - 5)ft².
20. The formula for the perimeter (or circumference) of a circle is π times the diameter of the circle. Using the radius of the circle, 1/π, the diameter is 2/π, so
π • 2/π = 2. The circumference of the circle is 2 inches.
The area of the circle is calculated with the equation πr², so
π(1/π)² = π • 1/(π²) = π/(π²) = π. The area is simply π in².
