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2 years ago

13

WILL GIVE BRAINLIEST

1 answer:

sveticcg [70]2 years ago

3 0

The answer is 2x15 which is 30ft

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If the mean weight of 4 backfield members on the football team is 222 lb and the mean weight of the 7 other players is 198 lb, w

hoa [83]

To find the Mean or Average you have to add up all numbers it is asking for which in case are 222 and 198.

so you will add 222+198

That will equal 420

Then you will divide with the amount added together which is 2

420/2=210

so the mean of the 11 people is 210 or 210lbs

5 0

3 years ago

Given two points on a line, write the equation of the line in slope intercept form. The points are (-4,10), (6,5). Please show a

Aleonysh [2.5K]

The slope is 1/2.
The y-intercept is 8.

Here is the equation:

$y=1/2x+8$

I hope this helps c:

6 0

3 years ago

Help.. please... my due is in 5 minutes

Diano4ka-milaya [45]

<h3>Answer:</h3>

y = x - 5

<h3>Step-by-step explanation:</h3>

If 5 is being subtracted from x, then it would look like x-5.

Since x-5 represents 5 being subtracted from x, y=x-5 is the correct answer because the other options aren't representing 5 subtracted from x.

3 0

2 years ago

Which of the following is a correct equation for the line passing through the

kipiarov [429]

Answer:

$2x-3y=-12$

Step-by-step explanation:

We can use the point-slope formula given by:

$y-y_1=m(x-x_1)$

The given line passes through the

point (-3,2) and having slope $m=\frac{2}{3}$ .

We substitute the given point and slope to get:

$y-2=\frac{2}{3}(x--3)$

$y-2=\frac{2}{3}(x+3)$

we clear the fraction to get;

$3y-6=2(x+3)$

$3y-6=2x+6$

$3y-2x=6+6$

$3y-2x=12$

Or in standard form:

$2x-3y=-12$

8 0

3 years ago

Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

Art [367]

Using the given center and point at the circumference, the equation of the circles are:

a) $(x - 5)^2 + (y - 2)^2 = 100$

b) $(x + 2)^2 + (y + 5)^2 = 169$

c) $(x - 5)^2 + (y + 1)^2 = 65$

<h3>What is the equation of a circle?</h3>

The equation of a circle of radius r and center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Item a:

Center C(5,2), hence $x_0 = 5, y_0 = 2$ .

The point at the circumference is A(11,10), hence:

$(x - 5)^2 + (y - 2)^2 = r^2$

$(11 - 5)^2 + (10 - 2)^2 = r^2$

$r^2 = 100$

Hence:

$(x - 5)^2 + (y - 2)^2 = 100$

Item b:

Center C(-2,-5), hence $x_0 = -2, y_0 = -5$ .

The point at the circumference is A(3,-17), hence:

$(x + 2)^2 + (y + 5)^2 = r^2$

$(3 + 2)^2 + (-17 - 5)^2 = r^2$

$r^2 = 169$

Hence:

$(x + 2)^2 + (y + 5)^2 = 169$

Item c:

Center C(5,-1), hence $x_0 = 5, y_0 = -1$ .

The point at the circumference is A(-2,-5), hence:

$(x - 5)^2 + (y + 1)^2 = r^2$

$(-2 - 5)^2 + (-5 + 1)^2 = r^2$

$r^2 = 65$

Hence:

$(x - 5)^2 + (y + 1)^2 = 65$

You can learn more about equation of a circle at brainly.com/question/24307696

4 0

2 years ago