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boyakko [2]
4 years ago
12

When we don't use prefixe ina binary compound​

Chemistry
2 answers:
Karolina [17]4 years ago
5 0

Answer:

Explanation:

Answer will be wrong

MA_775_DIABLO [31]4 years ago
4 0
Your answer will not be correct
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Measuring levels of pollutants, such as nitrogen oxide in the atmosphere, is an example of chemistry research that ____.
Paraphin [41]

Answer:

aims to benefit the environment is the correct answer.

Explanation:

The goal of Aims to the benefits environment is to provide everyone information, values, and skills which are required to preserve and protect the environment.

Aims to benefit the environment includes

  • To decrease emissions and reduce pollution.
  • To improve waste management methods.
  • To reduce the consumption of natural sources.
  • To minimize noise and different nuisances.

3 0
3 years ago
100.0 g of water was placed in a simple, constant-pressure calorimeter. The temperature of the water was recorded as 295.0 K. A
Marizza181 [45]

Answer:

296.05\ \text{K}

Explanation:

m_w = Mass of water = 100 g

c_w = Specific heat of water = 4.184\ \text{J/g K}

m_c = Mass of copper = 20 g

c_c = Specific heat of copper = 0.385\ \text{J/g K}

\Delta T_w = Temperature change in water = (T-295)

\Delta T_c = Temperature change in cooper = (353-T)

T = Final temperature of the system

The heat balance of the system is given by

m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}

The final temperature of the water is 296.05\ \text{K}.

7 0
3 years ago
Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward s
Simora [160]

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

3 0
3 years ago
A 0.100 M solution of chloroacetic acid 1ClCH2COOH2 is 11.0% ionized. Using this information, calculate 3ClCH2COO-4, 3H 4, 3ClCH
bearhunter [10]

Answer:

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = 1.36 x 10^-3

Explanation:

The reaction

CICH2COOH  ⇄ H+ (aq) + CICH2COO- (aq)

The initial concentration of CICH2COOH is 0.10 M , chloroacetic acid is 11.0% ionized.

let us calculate Ka

First , find change in concentration

since , 11% ionized

change in concentration = 0.10 X 11% = 0.011 M

Initial Concentration of CICH2COOH = 0.10 M

change in concentration of CICH2COOH = - 0.011 M

Equilibrium Concentration of CICH2COOH = 0.10 M - 0.011 M = 0.089 m

Initial Concentration of CICH2COO- = 0 M

change in concentration of CICH2COO- = + 0.011 M

Equilibrium Concentration of CICH2COO- = 0.011 M

Initial Concentration of H+ = 0 M

change in concentration of H+ = + 0.011 M

Equilibrium Concentration of H+ = 0.011 M

Therefore,

[CICH2COOH] = 0.089 M

[CICH2COO-] = 0.011 M

[H+] = 0.011 M

Ka = [H+][CICH2COO-] /[CICH2COOH]

Ka = (0.011 * 0.011) / (0.089)

Ka = 1.36 x 10^-3

6 0
3 years ago
How many grams of KCl (s) has been produced from the thermal decomposition of KClO3 (s) that produced 50.0 mL of O2 (g) at 25 de
geniusboy [140]

Answer:

The mass is m_{KCl} =  0.102 \ g

Explanation:

From the question we are told that

   The volume of oxygen produced is  V_o = 50mL  = 50 *10^{-3} L

    The temperature is T = 25 ^oC = 25* 273 = 298 K

     The pressure is  P = 1.0\  atm

From the ideal gas law we have that

      PV =  nRT

Where R is the gas constant  with the value

         R =  0.08206 \ atm \cdot L /mol K

  n is the number of moles making it the subject of the formula

          n = \frac{PV}{RT}

Substituting values

          n = \frac{1 * (50 *10^{-3}) }{0.08206 * 298}

          n =  2.045 *10^{-3} \  mol

From the chemical equation

      one mole of  KClO_3 produces one mole of  kCl and   \frac{3}{2} of oxygen

       x mole of  KClO_3 produces x mole of  kCl and   2.045 *10^{-3} \  mol of oxygen

So    x = \frac{2.045 *10^{-3}}{\frac{3}{2} }

      x =  \frac{2}{3} * 2.045 *10^{-3}

      x =  1.363 *10^{-3} \ mol

Now the molar mass of  KCl is a constant with a value

           M_{KCl} = 74.55  g/mol

Now the mass of KCl is mathematically evaluated as

          m_{KCl} = x * M_{KCl}

Substituting values

          m_{KCl} = 1.363 *10^{-3} * 74.55

         m_{KCl} =  0.102 \ g

6 0
3 years ago
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