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Scorpion4ik [409]
2 years ago
14

(a) what is the approximate ductility (%el) of a brass that has a yield strength of 230 mpa (33360 psi)?

Chemistry
1 answer:
ss7ja [257]2 years ago
3 0

Based on the calculations, the approximate ductility (%el) of this brass is equal to 2.3%.

<u>Given the following data:</u>

  • Yield strength = 230 mpa (33360 psi).

<h3>What is ductility?</h3>

Ductility can be defined as an important property of a material which determines its ability to become elongated due to the application of stress.

Mathematically, the ductility of a material can be expressed as percentage elongation in length:

\% el = \frac{\Delta L}{L_i} =\frac{L_f - L_i}{L_i}

<u>Where:</u>

  • L_i is the original length.
  • L_f is the final length.
  • \Delta L is the yield strength.

For this exercise, let us assume the original length of this brass is equal to 100 meters.

Substituting the parameters into the formula, we have;

\% el = \frac{230}{100}

Ductility = 2.3%.

Read more on ductility here: brainly.com/question/828860

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3 years ago
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Fynjy0 [20]

Answer:

Reagent A: PBr₃

Reagent B: Mg in Et₂O.

Explanation:

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In this case, your facing a problem in which a carboxylic acid is produced starting by an alcohol. More specifically, cyclopentanol must react with phosphorous tribromide in order to yield bromocyclopentane which is more likely to produce a carboxylic acid, therefore, reagent A is PBr₃.

On the other hand, by means of the production of the specified product, bromocyclopentane must react with carbon dioxide and magnesium in diethyl ether in acidic media to promote the production of the cyclopentanoic acid via the grignard reaction (substitution of the bromine by the carboxyle group), therefore, reagent B is Mg in Et₂O.

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2 years ago
If a reaction is reversible what are the relative amounts of reactant and product
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3 years ago
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8 0
3 years ago
Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
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