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Rina8888 [55]
2 years ago
12

What is the alkaline earth metal with the largest atomic number

Chemistry
2 answers:
frez [133]2 years ago
5 0
Radium, which has an atomic number of 88. The Alkaline earth metals are in the second column of the Periodic Table. Hope this helps! 
Helga [31]2 years ago
4 0
Alkaline earth metals are in the second column from the left of the periodic table. The metal with the largest atomic number is Radium with 88.
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Read 2 more answers
How many molecules are in 5.50 grams of AgNO3?
mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

  • Ag: 107.87 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

moles=\frac{5.50 grams*1 mole}{169.87 grams}

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}

molecules=1.95*10²²

<u><em>1.95*10²² molecules are in 5.50 grams of AgNO₃</em></u>

3 0
2 years ago
so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step
Nikolay [14]

Answer:

Empirical formula is CCl₄

Explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

            C                      :              Cl            

           0.64/0.64        :             2.6/0.64

            1                      :                4        

C : Cl  = 1 : 4

Empirical formula is CCl₄.

5 0
3 years ago
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