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Mice21 [21]
3 years ago
10

What experiments did Lavoisier do?

Chemistry
1 answer:
VikaD [51]3 years ago
8 0
He did experiments with combustion and gas's
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The combination of oxygen with other substances to produce new chemical products is called
Flauer [41]

Answer:

                 The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.

Explanation:

                     Oxidation reactions are defined as,

In terms of Inorganic chemistry:

                 (i) <u>Removal of Electrons: </u>

                            Example:  Mg  →  Mg²⁺  +  2 e⁻

                (ii) <u>Addition of Oxygen:</u>

                            Example:  2 Mg  + O₂  →  2 MgO

In terms of Organic chemistry:

                (i) <u>Addition of Electrons: </u>

                            Example:  Cl₂  +  2 e⁻   →   2 Cl⁻

                (ii) <u>Addition of Hydrogen:</u>

                            Example:  H₂CCH₂  +  H₂    →   H₃CCH₃

4 0
3 years ago
A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

8 0
3 years ago
The standard enthalpy of formation (ΔHf°) of calcium carbonate is –1207 kJ/mol. Which ONE of the equations below has ΔH° = –1207
Art [367]

Answer:

A) Ca(s) + C(s) + 3/2 O₂(g) → CaCO₃(s)

Explanation:

Standard enthalpy of formation of a chemical is defined as the change in enthalpy durin the formation of 1 mole of the substance from its constituent elements in their standard states.

The consituent elements of calcium carbonate, CaCO₃, in their standard states (States you will find this pure elements in nature), are:

Ca(s), C(s) and O₂(g)

That means, the equation that represents standard enthalpy of CaCO₃ is:

<h3>A) Ca(s) + C(s) + 3/2 O₂(g) → CaCO₃(s)</h3><h3 />

<em>Is the equation that has ΔH° = -1207kJ/mol</em>

3 0
3 years ago
staci is attending a music festival. the ticket to the festival costs $87.96, Staci pleans to purchase $30.00 t-shirts from the
ziro4ka [17]

The total amount that Staci had in hand is $200.00.

The ticket at that time costs $87.96.

One Tshirt costs, $30.00.

Now that she has paid ticket, she will deduct the ticket from the cash she has in hand, so as to know the amount she is remaining with.

Tha is, $200-$87.96 = $112.04.

∴ In hand Staci has $112.04 extra cash whereby she can purchase more t shirts.

To get the number of tshirt she can buy, she will divide the amount she has in hand by the amount per piece of t shirt.

For example, $112.04 / $30 = $3.73.

∴ Staci can only purchase threet shirts only at a total cost of $90 for all the t shirts which is $30 × 3 = $90.

Staci has excess of 22.04 after deducting ticket and the other amount she has used to purchase the extra t shirts.

That is, $112.04 - $90 = $22.04.

3 0
3 years ago
Read 2 more answers
What type of organism does this cell most likely belong to?
maks197457 [2]

Answer:

A) a plant

Explanation:

  • A plant cell consists of cytoplasm, chloroplast, nucleus, mitochondria, cell wall, and a Golgi apparatus. They represent a eukaryotic cell of green plants and there are various types of plant cells such as Parenchyma, Collenchyma, Sclerenchyma,  Xylem, Phloem, and the Epidermis.
4 0
3 years ago
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