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ki77a [65]
3 years ago
14

How does pH affect enzyme-catalyzed reactions? How does affect enzyme-catalyzed reactions? Energy stored in protons is used to d

rive endergonic reactions. The concentration of protons affects an enzyme's folded structure and reactivity. Proton concentration increases the kinetic energy of the reactants, enabling them to reach their transition state. Protons serve as substrates for most reactions.
Chemistry
1 answer:
Zolol [24]3 years ago
7 0

Answer:

The concentration of protons affects an enzyme's folded structure and reactivity.

Explanation:

Enzymes act within narrow pH limits (optimal reaction pH). Since most enzymes have a protein structure, the variation in pH or temperature affects their enzymatic activity.

To catalyze a reaction, an enzyme binds to one or more reagent molecules. These molecules are the substrates of the enzyme.

In some reactions, a substrate breaks into several products. In others, two substrates join together to create a larger molecule or to exchange parts. In fact, for any biological reaction that can occur to you, there is probably an enzyme to accelerate it.

The part of the enzyme where the substrate binds is called the active site.

The amino acid residues of the active site often have acidic or basic properties that are important for catalysis. Changes in pH can affect these residues and make binding with the substrate difficult.

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What is the partial pressure of carbon dioxide in a container that contains 3.63 mol of oxygen, 1.49 mol of nitrogen, and 4.49 m
lana66690 [7]

Answer:

Partial pressure of CO₂ is 406.9 mmHg

Explanation:

To solve the question we should apply the concept of the mole fraction.

Mole fraction = Moles of gas / Total moles

We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)

Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles

To determiine the partial pressure of CO₂ we apply

Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P

Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure

We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg

6 0
3 years ago
Read 2 more answers
If the input force applied to one end of a first-class lever is 8 N, and the fulcrum is located 6 m away from the input force bu
MatroZZZ [7]

Answer:

16 N

Explanation:

The ratio of output force to the input force is called mechanical advantage of the lever. Also, the ratio of input arm distance to the output arm distance is called mechanical advantage of the lever.

We have,

Input force = 8 N

Input arm distance = 6 m

Output arm distance = 3 m

We need to find the resulting output force. So,

\dfrac{F_o}{8}=\dfrac{6}{3}\\\\F_o=16\ N

So, the resulting output force is 16 N.

4 0
3 years ago
which occupies a larger volume, 600 g of water (with a density of 0.995 g/cm3 ) or 600 g of lead (with a density of 11.35 g/cm3
Montano1993 [528]
Water will occupy larger volume
5 0
3 years ago
An atomega has a mass of 53 an an atomic number of 26. How many neutrons does it have
Ghella [55]
26, protons and nuetrons will always be the  same

4 0
3 years ago
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A 100-mL graduated cylinder w
kicyunya [14]

Answer:

h=100.8cm

Explanation:

Hello,

In this case, considering the density and mass of both water and heptane we first compute the volume of each one:

V_{water}=\frac{m_{water}}{\rho _{water}}=\frac{34g}{1.00g/mL}=34mL\\  \\V_{heptane}=\frac{m_{heptane}}{\rho _{heptane}}=\frac{34.6g}{0.684g/mL}=50.6mL\\

Now, the total volume is:

V=50.6mL+34mL=84.6mL

Which is equal to:

V=84.6cm^3

Then, by knowing that the volume of a cylinder is πr²h or π(D/2)²h, we solve for the height as follows:

h=\frac{V}{\pi (D/2)^2} \\\\h=\frac{84.6cm^3}{\pi (3.16cm/2)^2} \\\\h=100.8cm

Best regards.

3 0
3 years ago
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