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SOVA2 [1]
3 years ago
12

Explain. How you would separate a mixture of water, sand, salt, and iron feelings into its four component parts

Chemistry
1 answer:
Goryan [66]3 years ago
8 0
Mix it. The salt will dissolve, eventually the sand and metal will settle. Pour out most of the water, let it evaporate leaving the salt. Use a magnet for the iron, which leaves the sand.
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they are apart of the life cycle

Explanation:

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Rubbing alcohol is less polar than water. Both are liquids at room temperature which One boils first? why?
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because both liquid are made from different substances.

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8 0
3 years ago
Calculate the molarity of a solution prepared by dissolving 1.495 moles of lioh in enough water to give a final volume of 750. m
zhenek [66]
Molarity can be defined as the number of moles of substance dissolved in 1 L of solution.
In the given question ,
number of LiOH moles - 1.495 mol
Dissolved volume - 750 mL
molarity is calculated for 1 L = 1000 mL
In 750 mL - 1.495 mol of LiOH is dissolved
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4 0
3 years ago
Solid magnesium has mass of 1300g and a volume of 743cm . what's the density of magnesium?
Lilit [14]
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3 0
3 years ago
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
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