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SOVA2 [1]
2 years ago
12

Explain. How you would separate a mixture of water, sand, salt, and iron feelings into its four component parts

Chemistry
1 answer:
Goryan [66]2 years ago
8 0
Mix it. The salt will dissolve, eventually the sand and metal will settle. Pour out most of the water, let it evaporate leaving the salt. Use a magnet for the iron, which leaves the sand.
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What is a potential benefit of fuel cell cars?
77julia77 [94]

Answer:

no recharging necessary

3 0
3 years ago
Read 2 more answers
If 61.5 moles of an ideal gas occupies 97.5 liters at 473 K, what is the pressure of the gas, in mmHg?
kiruha [24]
I’d say for the answer 13.13 mmHg?
5 0
2 years ago
the half of an oxidation-reduction reaction shows the iron gains. what does this electron gain mean for iron.
Nataly [62]

The correct answer is option C, that is, it is reduced.

In reduction and oxidation reactions, reduction refers to the loss of an oxygen atom from a molecule or the gaining of one or more electrons. A reduction reaction is observed from the perspective of the molecule being reduced, as when one molecule gets reduced, another one gets oxidized. The complete reaction is called a redox reaction.

In the given case, iron gains electrons mean that it is reduced.  


3 0
2 years ago
Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. True or false?.
wel

Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. It is false.

When hydrogen sulfide gas reacts with dioxygen gas, it produces water and solid Sulphur and not gaseous sulfur. The chemical equation of the given substances is :

                   2H2S +  O2 → 2S + 2H20

It is a redox reaction as both Oxidation and reduction happens in it. Oxidation of hydrogen sulphur to sulphur happens and reductions of oxygen to water takes place.  

if you need to learn more about chemical reaction of Hydrogen sulfide gas, click here

brainly.com/question/15842521?referrer=searchResults

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4 0
1 year ago
4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below
gayaneshka [121]

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

q_{rxn}=-q_{cal}

q_{cal}=c_{cal}\times \Delta T

where,

q_{rxn} = heat released by the reaction = ?

q_{cal} = heat absorbed by the calorimeter

c_{cal} = specific heat of calorimeter = 97.1kJ/^oC=97100J/^oC

\Delta T = change in temperature = (T_{final}-T_{initial})=(27.282-25.000)=2.282^oC

Now put all the given values in the above formula, we get:

q_{cal}=(97100J/^oC)\times (2.282^oC)

q_{cal}=221582.2J=221.6kJ

As, q_{rxn}=-q_{cal}

So, q_{rxn}=-221.6kJ

Thus, the heat of the reaction is -221.6 kJ

6 0
3 years ago
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