Answer:
Solution A is a Weak Alkali, Solution B is a strong Acid.
Explanation:
At pH 10, the colour is blue, therefore it's a weak alkali.
At pH 1, the colour is red, therefore it's a strong Acid.
Answer:
757.5 kPa
Explanation:
Boyle's law states that p1 * v1 = p2 * v2
v1 = 12 mL
v2 = 8 mL
p1 = 505 kPA
p2 = ?
(505)(12) = (p2)(8)
6060 = (p2)(8)
p2 = 757.5
B. 6.45 mol F2
The mole ratio here is 3 mol F2 for every 1 mol S. Multiply 2.15 mol S by 3 to get the mol of F2 needed.
Answer:
55.9 g KCl.
Explanation:
Hello there!
In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

Thus, solving for the moles of solute, we obtain:

Since the density of water is 1 kg/L, we obtain the following moles:

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

Regards!