12 moles are needed because stoichiometry is 1:2
D
Answer:
590 g CaCl₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
5.3 mol CaCl₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol
<u>Step 3: Convert</u>
<u />
= 588.194 g CaCl₂
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
588.194 g CaCl₂ ≈ 590 g CaCl₂
C. Of the products is equal to the reactants.
Good luck out there! :)
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