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Allushta [10]
2 years ago
5

Solve the science problem

Chemistry
2 answers:
viva [34]2 years ago
4 0

Answer:

ELEMNT  MBOSL IP IX R2 I

Explanation:

erastovalidia [21]2 years ago
3 0

Answer:

It's C

Explanation:

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How does energy usage compare during different seasons of the year
omeli [17]
The residential end-use sector has the largest seasonal variance, with significant spikes in demand every summer and winter. Virtually all homes that have air conditioning use electricity as the main source of cooling in the summer, while winter heating needs are met by a variety of fuels. Some homes use electric resistance heating and electric heat pumps, but even homes with other heating fuels such as natural gas or fuel oil still use some electricity to power furnace fans, boiler circulation pumps, and compressors.
The commercial sector experiences less variance in electricity use, although it shows a noticeable increase in the summer and a slight increase in the winter. Compared to the residential sector, a smaller portion of commercial sector energy consumption is devoted to heating, cooling, and ventilation. However, other energy fuels beyond electricity can be used in the commercial sector to meet both heating and cooling needs. For example, some commercial buildings use natural gas-fired chillers for cooling.
The industrial sector's demand for electricity is relatively flat (with just a slight increase in the summer) because a much smaller portion of its energy consumption (electric and otherwise) is used for heating and cooling. Economic variables generally play a larger role in industrial energy use than weather-related factors. However, seasonal changes can affect industrial activity. For example, in the refining industry, different seasonal slates of petroleum products as well as different seasonal processes may affect electricity needs.
6 0
3 years ago
Water is a source of ______________ for chemical reactions in cells.
S_A_V [24]

Answer:Electrolyte

Explanation:Electrolyte is a compound either in solution or in molten form that gets decomposed by thee passage if electricity through it. Water is polar,but a weak electrolyte, so in cells,water is used as an electrolyte

5 0
2 years ago
A hot air ballon will rise in air because:
solmaris [256]

Answer: C

Explanation:

Hot air is a lot less dense for a few reasons. Hot air essentially means the particles have more kinetic energy, and move around a lot more. Cold air is dense because the particles move a lot less, have less energy, and are closer together.

7 0
2 years ago
Read 2 more answers
How many significant figures are in 136,000 ml?
WINSTONCH [101]

Answer:

There are 3 sig figs

Explanation:

Sig figs are the amount of figures counting from the left side of the number until you reach the first zero. Starting from the left, I counted one, three, and six. That's 3 numbers, and therefore, that's how we got our answer. The only exception is when there is a decimal. Then all the numbers before the decimal, despite whether or not they're zeros, are sig figs.

8 0
3 years ago
Read 2 more answers
Rank the following fertilizers in decreasing order of mass percentage of nitrogen:
charle [14.2K]
<h3>Answer:</h3>

        NH₃ > NH₄NO₃ > (NH₄)₂HPO₄ > (NH₄)₂SO₄ > KNO₃ > (NH₄)H₂PO₄

<h3>Soution:</h3>

In (NH₄)₂HPO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂HPO₄  =  132.06 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂HPO₄ × 100

Mass %age  =  28 g.mol⁻¹ / 132.06 g.mol⁻¹ × 100

Mass %age  =  21.20 %

In (NH₄)₂SO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂SO₄  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂SO₄ × 100

Mass %age  =  28 g.mol⁻¹ / 132.14 g.mol⁻¹ × 100

Mass %age  =  21.18 %

In KNO₃:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of KNO₃  =  101.10 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of KNO₃ × 100

Mass %age  =  14 g.mol⁻¹ / 101.10 g.mol⁻¹ × 100

Mass %age  =  13.84 %

In (NH₄)H₂PO₄:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of (NH₄)H₂PO₄  =  115.03 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)H₂PO₄ × 100

Mass %age  =  14 g.mol⁻¹ / 115.03 g.mol⁻¹ × 100

Mass %age  =  12.17 %

In NH₃:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of NH₃  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of NH₃ × 100

Mass %age  =  14 g.mol⁻¹ / 17.03 g.mol⁻¹ × 100

Mass %age  =  82.20 %

In NH₄NO₃:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of NH₄NO₃  =  80.04 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of NH₄NO₃ × 100

Mass %age  =  28 g.mol⁻¹ / 80.04 g.mol⁻¹ × 100

Mass %age  =  34.98 %

5 0
3 years ago
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