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Elina [12.6K]
3 years ago
6

A polynomial function has a root of –3 with multiplicity 2, a root of 0 with multiplicity 1, a root of 1 with multiplicity 1, an

d a root of 3 with multiplicity 2. If the function has a positive leading coefficient and is of even degree, which could be the graph of the function?
Mathematics
2 answers:
klasskru [66]3 years ago
7 0

The answer is A for Edge

vitfil [10]3 years ago
4 0
Based on the given roots and their multiplicities, the function is made of the following factors:
f(x) = x (x + 3)^2 (x - 1) (x - 3)^2

The roots represent the point in the graph where they touch the x-axis. With the given condition that the function has a positive leading coefficient and is of even degree, the group of the function touches the x-axis at the roots and is curved upwards.
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snow_lady [41]
There is a really easy way to find this out I can't really help you so if you just look it up on google you should get your awnser

8 0
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Answer:

8n

Step-by-step explanation:

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6 0
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Two complementary angles are in the ratio of 1:5. find the measure of the larger angle?
Luden [163]
First you set up an equation using a variable:
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7 0
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eimsori [14]

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7 0
3 years ago
Read 2 more answers
In quadrilateral ABCD,AB produced is perpendicular to DC produced.If A=44° and C=148°,calculate D and B.
7nadin3 [17]
Let AB extended intersect DC extended at point E 
<span>We now have right triangle BEC with E = 90 degrees </span>

<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
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<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>

<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
5 0
3 years ago
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