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lana [24]
2 years ago
10

An airplane refuels in Bakersfield and continues on to Fresno. It travels an average speed of 610 km/h. IF the trip takes 2.75 h

ours, what is the flight distance between Bakersfield and Fresno?
Physics
1 answer:
rusak2 [61]2 years ago
8 0

2.75x610km

1220+7.5x61

1220+427 ... just over

1647

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What magnitude charge creates a 32.08 N/C electric field at a point 2.84 m away?
sammy [17]

Answer:

Q = 29.4 x 10⁻⁹ C.

Explanation:

Electric field due to a charge Q at distance d is given by coulomb law as follows

Electric field

E = k Q /d²

where for air k which is a constant is 9 x 10⁹

E=\frac{k\times Q}{d^2}

Given E = 32.08 , d = 2.84 m

Putting these values in the relation above, we have

[tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}[/tex]

Q = 29.4 x 10⁻⁹ C.

5 0
2 years ago
Find the resistance of an electric light bulb if a current of 0.08 A flows when the potential difference across the bulb is 120
lora16 [44]
U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
8 0
3 years ago
an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the devi
andreev551 [17]

Answer: R=24.2Ω

Explanation: <u>Power</u> is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

P=V.i

P=R.i²

P=\frac{V^{2}}{R}

The resistance of the system is:

P=\frac{V^{2}}{R}

R=\frac{V^{2}}{P}

R=\frac{110^{2}}{500}

R = 24.2Ω

<u>For the device, resistance is 24.2Ω.</u>

4 0
3 years ago
A car travels 200km in 3.0 hours. Determine the average velocity of the car
Masja [62]

Answer:

<h2>66.67 km/hr</h2>

Explanation:

The average velocity of the car can be found by using the formula

a =  \frac{d}{t }  \\

d is the distance

t is the time taken

From the question we have

a =  \frac{200}{3}  \\  = 66.66666...

We have the final answer as

<h3>66.67 km/hr</h3>

Hope this helps you

4 0
3 years ago
Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light
professor190 [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

\theta_{max} =18.38^o

b

New  n_{cladding} =1.491

Explanation:

 From the question we are told that

          The refractive index of the core is  n_{core} = 1.497

         The refractive index of the cladding  is   n_{cladding} = 1.421

Generally according to Snell's law

      n_{core} * sin(90- \theta) = n_{cladding} * sin (90)

Where \theta_{max} is the largest angle a largest angle a ray will make with respect to the interface of the fiber and experience total internal reflection

      \theta_{max} = 90 - sin^{-1} [\frac{n_{cladding}}{n_{core}} ]

       \theta_{max} = 90 - sin^{-1} [\frac{1.421}{1.497}} ]

      \theta_{max} =18.38^o

Given from the question the the largest angle is  5°

Generally the refraction index of the cladding is mathematically represented as

           n_{cladding} = n_{core} * sin (90 - 5)

          n_{cladding} =1.491

       

5 0
3 years ago
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