Ask question

Ask question

All categories

3 years ago

10

An airplane refuels in Bakersfield and continues on to Fresno. It travels an average speed of 610 km/h. IF the trip takes 2.75 h

ours, what is the flight distance between Bakersfield and Fresno?

1 answer:

rusak2 [61]3 years ago

8 0

2.75x610km

1220+7.5x61

1220+427 ... just over

1647

You might be interested in

;-; please help me....

sineoko [7]

The answer is 24N. Since the body is moving with constant velocity all the forces must balance (equal & opposite)

5 0

3 years ago

Select the correct location on the image.<br> Identify the magnetic north pole of Earth’s magnet.

OverLord2011 [107]

The magnetic north pole of the earth's magnet is in the geographic south pole.

There are two magnetic and geographic poles each, north and south
The two geographic poles are the locations where the earth's axis of rotation passes through which is imaginary
The magnetic north and south poles are not the same as the geographic north and south poles
In a compass, the needle points to the magnetic north pole
By convention, the magnetic north pole corresponds to the geographic south pole
The magnetic south pole corresponds to the geographic north pole
The magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south pole

The magnetic north pole of the earth's magnet is the geographic south pole.

Learn more about earth's magnetism here:

brainly.com/question/3928159

#SPJ10

8 0

2 years ago

In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into t

Pie

Answer:

A) $Q_a=74256\ J$

B) $Q=93562560\ J$

Explanation:

Given:

temperature of air, $T_a=-19+273=254\ K$

temperature of lungs, $T_l=37+273=310\ K$

specific Heat exchanged from the lungs , $c_l=0.47\ J.kg^{-1}.K^{-1}$

specific heat of air, $c_a=1020\ J.kg^{-1}.K^{-1}$

mass of 1 L air, $m'=1.3\ kg$

breath rate, $b=21\ breath.min^{-1}$

A)

Now,

amount of heat needed to warm the air of lungs to the body temperature:

$Q_a=m'.c_a.\Delta T$

$Q_a=1.3\times1020\times (310-254)$

$Q_a=74256\ J$

B)

Amount of heat lost per hour:

<u>No. of breaths per hour:</u>

$B=b.60$

$B=21\times 60$

$B=1260$

<u>Now the total loss of energy in 1 hr.:</u>

$Q=Q_a.B$

$Q=74256\times 1260$

$Q=93562560\ J$

7 0

4 years ago

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 252 N in the negative x di

pentagon [3]

(a) 252 N, opposite to the applied force

There are two forces acting on the refrigerator in the horizontal direction:

- the pushing force of 252 N, F, forward

- the frictional force, Ff, pulling backward

In this case, the refrigerator is not moving: this means that its acceleration is zero. According to Newton's second law, this also means that the net force acting on the refrigerator is also zero:

$\sum F = ma = 0$

So we have

$F-F_f = 0$

which means that the frictional force is equal in magnitude to the pushing force:

$F_f = F = 252 N$

and the direction is opposite to the pushing force.

(b) 334.8 N

The force that must be applied to the refrigerator to make it moving is equal to the maximum force of friction, which is given by:

$F_{max} = \mu mg$

where

$\mu = 0.61$ is the coefficient of static friction

m = 56 kg is the mass of the refrigerator

g = 9.8 m/s^2 is the acceleration of gravity

Substituting:

F_max = (0.61)(56 kg)(9.8 m/s^2)=334.8 N

6 0

3 years ago

Is there any science behind unicorns/ pegasis?

hjlf

Pegasus<span>, considering the fact that </span>unicorns<span> were, and still are, real. </span>

5 0

3 years ago

Read 2 more answers